Physics Finding Total Distance?

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Homework Help Overview

The problem involves calculating the total distance traveled by John and his sled dogs under varying conditions of speed and number of dogs. The scenario includes a sled journey where 5 dogs initially pull the sled, but 2 escape, resulting in a change of speed and an extended travel time. The original poster seeks clarification on the implications of these changes on the total distance covered.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the implications of the number of dogs on distance traveled and the relationship between speed and time. There is confusion about how different numbers of dogs affect the distance covered in the same time frame. Some participants attempt to set up equations based on the given information, while others question the assumptions made regarding the distances and times.

Discussion Status

Participants are actively engaging with the problem, attempting to derive equations based on the information provided. There is recognition of potential misinterpretations of the problem statement, and some participants are exploring different scenarios and their implications on the calculations. While there is no consensus on the correct approach yet, several lines of reasoning are being examined.

Contextual Notes

There is uncertainty regarding the interpretation of the problem's wording, particularly concerning the timing of the arrival and the implications of the dogs escaping. Participants are also grappling with the assumptions that can be made about the distances covered in relation to the number of dogs and their speeds.

  • #31
RichardT said:
ok, one more thing, how do you assume that the area of H and G equal the area of F and E if only you know that they have the same height. You don't know the widths right? Because since i know that the width of H and G = 36 and the width of F and E equal 24, wouldn't the distances be different??
EDIT: wait that's only assuming he travels 50 km in 24 hours which you can't so how did you get H and G equal to E and F?

Note that using the full team for an extra 50km, made section K 24hrs wide, not the time taken to cover the 50km.(that was 36hrs it turns out).
 
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  • #32
Ok so area G and H are equal to area of E and F because area of J = the area of K?
 
  • #33
RichardT said:
Ok so area G and H are equal to area of E and F because area of J = the area of K?

Correct! and I suspect you find it surprising - but it was all in the original information.

when the dogs left - 48 hours late
If the dogs stayed on for an extra 50km, only 24 hours late so the area J is one half of D, and thus J = K
 

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