Physics Fundamentals: Work Done

[learn2physics]

Homework Statement

This is a theoretical question that I do not quite fully understand. " An object moving up a 6m ramp to a height of 2m v.s vertically moving an object up 2m." Someone tell me the work done is the same for both scenario. How are they the same? Surely kinetic energy is involved in moving the 6m ramp, am I right?

Homework Equations

Work done = Force x Distance
Kinetic Energy = 0.5*mass*velocity^2
Gravitational Potential Energy = mass*acceleration due to gravity*height

The Attempt at a Solution

Can someone explain why moving an object vertically up has the same work done as moving the object up the ramp, both at the same height?

 

[CWatters]

Work out force * distance in both cases.

Assume that the object starts from rest and coasts to a halt at the top in both cases - that allows you to forget about KE.