Physics Gravity Problem and Kinetic Friction

Click For Summary
SUMMARY

The forum discussion centers on calculating the mass of Mercury and Neptune using projectile motion principles. Two astronauts hit a 142 g ball with a force of 52 N at a 40-degree angle on both planets, resulting in distances of 700 m on Mercury and 100 m on Neptune. The participants emphasize the need for understanding gravitational formulas, specifically M = ar²/G, and the importance of using projectile motion equations to determine acceleration and final velocity. The conversation highlights the necessity of showing detailed work to solve the problem effectively.

PREREQUISITES
  • Understanding of Newton's Second Law (F=MA)
  • Knowledge of gravitational formulas (M = ar²/G)
  • Familiarity with projectile motion equations
  • Basic concepts of kinematics, including distance and acceleration
NEXT STEPS
  • Research projectile motion equations and their applications in real-world scenarios
  • Study the derivation and application of the gravitational formula M = ar²/G
  • Learn how to calculate acceleration using initial velocity and distance
  • Explore momentum conservation principles in relation to projectile motion
USEFUL FOR

Students in physics, educators teaching kinematics, and anyone interested in understanding gravitational effects on projectile motion.

yomo710
Messages
8
Reaction score
0

  1. Two astronauts are trying to figure out the mass of Mercury and the mass of Neptune. The astronauts decide to hit a 142 g ball with a bat on each planet and see how far it goes. They know the radius of mercury is 2,440 km and the radius of Neptune is 24,622 km. On mercury one astronaut hits the ball with a force of 52n over .1 seconds at a 40 degrees and it travels 700m. The second astronaut hits the ball with the same force at the same angle on Neptune and it travels 100m. What is the mass of the two planets?

For the planet problem, I attempted to use the formula to find the gravity but need the mass of the planet. Then I attempted to find the mass but need the gravity. I don't even know where to start.
 
Last edited:
Physics news on Phys.org
Welcome to PF;
You've shown us a general outline of how you are approaching the problem, but we need to see your best attempt in more detail.
You clearly know where to start, and you appear to starting in the right place: using some sort of gravity formula.
But I cannot advise you because I don't know which gravity equation nor how you have applied it.
 
Simon Bridge said:
Welcome to PF;
You've shown us a general outline of how you are approaching the problem, but we need to see your best attempt in more detail.
You clearly know where to start, and you appear to starting in the right place: using some sort of gravity formula.
But I cannot advise you because I don't know which gravity equation nor how you have applied it.

Sure! As far as the planet question, I decided to use the M = ar^2/G formula. I have every part beside the mass (which I am trying to solve for) and the acceleration. I feel as if the acceleration is what is holding me back of figuring out both problems. But I do not know which formula to use for acceleration because I do not have the final velocity. When I do use d = vi(t) + 1/2 at^2 I get that the acceleration is 140,000 but I do not think that that is correct.

I also used the F=MA formula to get the acceleration that way but I get 366.197 as my acceleration and that does not seem correct.
 
d and a are perpendicular. Did you make use of the 40 degrees ? Ever do projectile trajectories ?
 
BvU said:
d and a are perpendicular. Did you make use of the 40 degrees ? Ever do projectile trajectories ?
I did not. I faintly understand projectile trajectories. How could I use and apply it?
 
By doing the exercise :) It's the only way. Want to know where to start ? Read your textbook or google around. Some of the formulas are here on PF.

PF principle is: help all you can, but don't take the exercise away from the student. He/she needs it.

"When I do use d = vi(t) + 1/2 at^2 I get that the acceleration is 140,000 but I do not think that that is correct." Show your work in detail and help is on the way.
 
BvU said:
By doing the exercise :) It's the only way. Want to know where to start ? Read your textbook or google around. Some of the formulas are here on PF.
That puts me at my original problem. I do not know the final velocity or acceleration.
 
You know the initial velocity magnitude and angle, so speed in vertical and in horizontal direction.
No force in the horizontal direction, so you can recover the time of flight.
Vertically the trajectory goes from initial height to final height according to your formula, where the only unknown is now a.
Just for the fun of it you can calculate final velocity magnitude and angle. You' ll be surprised !
 
BvU said:
You know the initial velocity magnitude and angle, so speed in vertical and in horizontal direction.
No force in the horizontal direction, so you can recover the time of flight.
Vertically the trajectory goes from initial height to final height according to your formula, where the only unknown is now a.
Just for the fun of it you can calculate final velocity magnitude and angle. You' ll be surprised !
Would using the range formula instead be better?
 
  • #10
yomo710 said:
Would using the range formula instead be better?
Well you're right. I guess I could use it but it would be more work for me. The question is asking about the canon being pushed back, will projectiles help?
 
  • #11
Home, home on the range ? The word has many meanings. That's why we use formulas. What range formula ? (And it's probably exactly the same, so no "better" and no "worse" either. -- To me better would mean more insightful )
 
  • #12
yomo710 said:
Well you're right. I guess I could use it but it would be more work for me. The question is asking about the canon being pushed back, will projectiles help?
By now we have two threads in shambles ! Totally incomprehensible. What happened to the cannon recoil exercise ? Did you figure out it was a matter of momentum conservation, followed by linear decelerated motion ?
 

Similar threads

  • · Replies 18 ·
Replies
18
Views
2K
Replies
14
Views
3K
Replies
48
Views
8K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 10 ·
Replies
10
Views
5K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 17 ·
Replies
17
Views
4K
  • · Replies 8 ·
Replies
8
Views
18K
  • · Replies 1 ·
Replies
1
Views
3K
  • · Replies 7 ·
Replies
7
Views
2K