Physics HW help? Normal Force between two objects?

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Homework Help Overview

The discussion revolves around a physics problem involving three blocks on a frictionless table, where a horizontal force is applied to one of the blocks. The participants are exploring the concepts of normal force and acceleration in relation to the blocks' masses and the applied force.

Discussion Character

  • Exploratory, Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to calculate the mass of the second block and is uncertain about how to determine the normal force between the second and third blocks. Some participants suggest using free body diagrams to analyze the forces acting on the blocks.

Discussion Status

Participants are actively engaging with the problem, with one providing a calculation for the force acting on the third block. There is a recognition of the relevance of this force in the context of the normal force, although there is no explicit consensus on the final answer.

Contextual Notes

There is a mention of significant figures in the context of rounding the normal force, indicating that precision in calculations is being considered. The original poster also notes the absence of a figure that could aid in visualizing the problem setup.

VoNi
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Physics HW help!? Normal Force between two objects?

Hi, I've had trouble trying to gigure out this problem! I would really appreciate the help!

The Problem:

Three blocks rest on a frictionless, horizontal table (see figure below), with m1 = 7 kg and m3 = 12 kg. A horizontal force F = 103 N is applied to block 1, and the acceleration of all three blocks is found to be 3.4 m/s2.

A. Find m2
B. What is the normal force between blocks 2 and 3?
I coouldnt post the figure(picture) but I can explain it.. The three blocks are all lined up against each other. So block 1(m1) is first, then block two(m2) is right next to block1, then block 3(m3) is against block 2.. they are all lined up on top of the table.. side by side..
Relevant equation:

I found the mass of block 2 by doing F=ma. or M= F/A
7+12+m2= 103/3.4
19+m2= 30.29
m2= 11.29

So M2 is 11.29

My only problem is that I don't know how to find the normal force between blocks 2 and 3


Attempt at a Solution:

The way i tried to find the solution was figuring out what force is acting on block three so that it can accelerate 3.4 m/s^2.
I did:
F=m*a
F=12*3.4
F= 40.8

Now, is 40.8 the normal force between block two and three or is that just an irrelevant number?

Thank you so much for the help!
 
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VoNi said:
The way i tried to find the solution was figuring out what force is acting on block three so that it can accelerate 3.4 m/s^2.
very good.
I did:
F=m*a
F=12*3.4
F= 40.8
Yes, but don't forget, F is actually F_net (in Newtons, don't forget the units)
Now, is 40.8 the normal force between block two and three or is that just an irrelevant number?
It is very relevant. If F_net = 40.8 N, what forces act on that block in the x direction? Draw a free body diagram of block 3. Is F_net and and F_normal the same??
 


Thank you SO much! that was very helpful! and the normal force, is 40.8 N. Thanks for taking the time to help me out! =)
 


You are welcome. Note that the normal force should probably (I think) be rounded off to 41 N (it's a significant figure thing), but your answer is essentially correct. Wecome to PF!
 

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