Physics Kinematics: Larry's Peach

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SUMMARY

Larry throws a peach vertically upward from a height of 1.2m with an initial velocity of 3.2m/s. The acceleration due to gravity is -9.81m/s². Using the kinematic equation Vf² = Vi² + 2a(delta x), the maximum height can be calculated. The solution involves determining the final velocity (Vf) at the peak and solving for the change in height (delta x).

PREREQUISITES
  • Understanding of kinematic equations
  • Knowledge of gravitational acceleration
  • Basic algebra skills for solving equations
  • Familiarity with vertical motion concepts
NEXT STEPS
  • Study the derivation of kinematic equations
  • Learn about projectile motion and its applications
  • Explore the concept of maximum height in vertical motion
  • Practice solving problems involving initial velocity and acceleration
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Students studying physics, educators teaching kinematics, and anyone interested in understanding vertical motion dynamics.

lilwigz
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Homework Statement


Larry throws a peach vertically upward from a height of 1.2m with an initial velocity of 3.2m/s. What is the maximum height the peach reaches?


Homework Equations



a= -9.81m/s^2

The Attempt at a Solution


I used the equation Vf^2=Vi^2+2a(delta x)
 
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lilwigz said:

The Attempt at a Solution


I used the equation Vf^2=Vi^2+2a(delta x)

And what did you get?
 

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