Physics Lab Questions: Rubber Band & Force Probe

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SUMMARY

The discussion centers on the effects of a rubber band on force measurements using a force probe in a physics lab setting. Participants initially predicted that the rubber band would not transmit force perfectly due to its upward pull, but experimental data contradicted this assumption. The correct method for calculating the percentage of stretch in a rubber band is outlined as (stretched length - original length) / (original length) x 100%. The conversation emphasizes the importance of understanding static equilibrium and the transmission of force in elastic materials.

PREREQUISITES
  • Understanding of static equilibrium in physics
  • Knowledge of force probes and their applications
  • Familiarity with elastic properties of materials, specifically rubber bands
  • Basic mathematical skills for calculating percentages and ratios
NEXT STEPS
  • Research the principles of static equilibrium and force transmission
  • Explore the mechanics of elastic materials and their behavior under load
  • Learn about the calibration and use of force probes in experimental physics
  • Study the mathematical concepts of ratios and percentages in physical measurements
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Physics students, educators, and laboratory technicians seeking to deepen their understanding of force measurement and the behavior of elastic materials in experimental setups.

Bashyboy
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Okay, I am working on my physics lab, and I have a few questions regarding it.

First, we are asked to make a prediction: "Predict how you think the presence of a rubber band will affect the force felt by the force probe from the rubber band compared to masses hung directly from the hook?" My lab partners and I thought that the force wouldn't transmit perfectly, because the rubber-band would pull upwards. Our data proved that that wasn't the case. Was are prediction truly wrong? Or, perhaps, did we set something up wrongly?

Also, say I have a rubber band, and I hang it from some hook; I measure its length, and then I put some weight on it, and measure it again. How would I write the amount of stretch as a percentage?
 
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The prediction was truly wrong, as is evident from the experimental data.

The percentage is (stretched length - original length) / (original length) x 100%.
 
Okay, I am just having a hard time understanding why it was wrong. And why does subtracting the stretched from the original length, then dividing by the original length and multiplying by 100% give you the percentage of stretch. I am sorry, I just don't seem to understand how to interpret ratios.

I am sorry if this information seems evident to you, but I have an dreadful intuition, and I always need to know why; sometimes it is quite bothersome.
 
Last edited:
For the prediction, intuitively one might think that a force can only be "absorbed" by an acceleration. If a system is in a static equilibrium, then a force acting on one object will be "transmitted" by the object to its support (or "distributed" among multiple supports), where it will be canceled by the reaction force; it is never absorbed by a stationary object.

For the percentage, I am not sure what exactly your problem is. A percentage is a ratio of a special kind, whose denominator is one hundred. A ratio with one denominator can always be converted to an equal ratio with another denominator, thus every ratio can be expressed as a percentage.
 
So, a rubber band in series will stretch twice the amount of a single rubber band with the same force being applied, is this a correct assumption?
 
Each band will stretch the amount it would stretch individually - because the lower band stretches and the transmits the same force on the upper band. The total extension is, correctly, twice that. This is why the extension under force is measured as a ratio: it is always the same (for a given force), but the absolute extension depends also on the original length.
 
Now, what would not make the lower band transmit the force perfectly to the upper band?
 
Only some other force or motion. The other force might be static friction.
 

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