Physics (Net Forces/Newton's laws)

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The discussion revolves around two physics problems involving net forces and Newton's laws. For the hot-air balloon, the resultant force was calculated as 400 N northward and 250 N westward, but the participant is unsure how to determine the angle clockwise from the leftward force. The suggestion is to use the Pythagorean Theorem for magnitude and trigonometric functions for the angle. In the second problem, a 1750 kg car moving at a constant speed of 1.92 m/s has a net force of zero, as constant speed indicates no acceleration. Clarification is provided that acceleration is necessary for calculating net force, and since the car is not accelerating, the net force remains zero regardless of direction.
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Alright well I have 2 questions I am stuck on.

first is:

Four forces act on a hot-air balloon, shown from the side in the figure below. Find the magnitude and direction of the resultant force on the balloon if F1 = 4600 N, F2 = 1250 N, F3 = 1000 N, and F4 = 4200 N.


F1 is pointing up, F4 is pointing down, F2 is pointing left and F3 is pointing right.

It asks for the force in N and at what degree clockwise from F2.

I got the force to be 300 N northward, and 250 N to the lef (west). I don't get how to get the Degree(direction) clockwise from F2. Any help?



And the other problem is:
An 1750 kg car is moving to the right at a constant speed of 1.92 m/s.

(a) What is the net force on the car?
_______ N to the right
(b) What would be the net force on the car if it were moving to the left?
_______ N to the left

I don't really know what to do here. i just used F=MA but it was wrong. i don't think 1.92 m/s can be used since it isn't acceleration but i don't really know what to do. any help?
 
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austin1250 said:
Alright well I have 2 questions I am stuck on.

first is:

Four forces act on a hot-air balloon, shown from the side in the figure below. Find the magnitude and direction of the resultant force on the balloon if F1 = 4600 N, F2 = 1250 N, F3 = 1000 N, and F4 = 4200 N.


F1 is pointing up, F4 is pointing down, F2 is pointing left and F3 is pointing right.

It asks for the force in N and at what degree clockwise from F2.

I got the force to be 300 N 4600-4200 = 400[/color]northward, and 250 N to the lef (west). I don't get how to get the Degree(direction) clockwise from F2. Any help?
You have the components of the resultant, can you find the magnitude of the resultant using the Pythagorean Theorem? Can you find the angle of the resultant using the trig properties of a right triangle?
And the other problem is:
An 1750 kg car is moving to the right at a constant speed of 1.92 m/s.

(a) What is the net force on the car?
_______ N to the right
(b) What would be the net force on the car if it were moving to the left?
_______ N to the left

I don't really know what to do here. i just used F=MA but it was wrong. i don't think 1.92 m/s can be used since it isn't acceleration but i don't really know what to do. any help?
You must use the acceleration. What is the car's acceleration if it is moving at constant speed?
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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