Physics Problem: Work Done by Friction w/ Bullet & Wood

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SUMMARY

The physics problem involves calculating the work done by friction when a bullet of mass 2g embeds itself in a wooden block of mass 0.498 kg, causing the block to slide 0.2m before stopping. The coefficient of friction is given as 0.4. Using the formula for work done by friction, W = f_friction * d, where f_friction is the frictional force calculated as f_friction = μ * m * g, the work done can be determined. The total mass of the system is 0.5 kg, and the work done by friction is calculated to be 3.92 Joules.

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Physics problem?
Suppose you shoot a bullet of mass 2g into a wooden block of mass 0.498 kg resting on the table. the bullet gets stuck in the wood, and the block slides a distance of 0.2m before it comes to rest again. how much work is done by the friction if the block with the bullet slides a distance of 0.2m on te table with a frictional coefficient of 0.4?
 
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Hint: What's the definition of work?
 
Check the definition of work. The relationship between the coefficient of friction and the normal is basically all you need to know because they gave you the distance.
 
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