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Alright.

The Question states:

The drawing shows an equilateral triangle, each side of which has a length of 2.00 cm. Point charges are fixed at each corner, as shown. The 400 mC charge experiences a net force due to the charge q A and qB. This net force points vertically downward in the drawing and has a magnitude of 405 N. Determine the magnitude and algebraic sighs of the charges qA and qB.

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This is what I did:

(1) I know that centimeters are supposed to be converted to meters

2.00*10-6

(2) Two vectors A & B are added together to produce a third vector C = A + B .

(3) When the triangle formed is not a right triangle:

the magnitude of the vector sum can be found by using the Law of Cosines or the Law of Sines

meaning:

4.00*10-6

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1

so now I am lost

HELP!!