Please help me with this question, I am a complete physics newbie who is lost… Alright. The Question states: The drawing shows an equilateral triangle, each side of which has a length of 2.00 cm. Point charges are fixed at each corner, as shown. The 400 mC charge experiences a net force due to the charge q A and qB. This net force points vertically downward in the drawing and has a magnitude of 405 N. Determine the magnitude and algebraic sighs of the charges qA and qB. ￼ This is what I did: (1) I know that centimeters are supposed to be converted to meters 2.00*10-6 (2) Two vectors A & B are added together to produce a third vector C = A + B . (3) When the triangle formed is not a right triangle: the magnitude of the vector sum can be found by using the Law of Cosines or the Law of Sines meaning: 4.00*10-6 ----------------------- 1 so now I am lost HELP!!