Piece of quartz mixed with gold

In summary: Define fraction - is that by weight or by volume?Fraction in this case refers to volume fraction, since density is given in units of g/cm^3.
  • #1
Arcany
3
0

Homework Statement


Piece of quartz containing gold weights 102,5g and average density is 7,98g/cm3. Density of quartz is 2,65g/cm3. How much does gold weight?

Homework Equations


ρ=m/V
avg.ρ= m1+m2/V1+V2

The Attempt at a Solution


Using average density I find that volume of this piece is 12,84cm3. ρ=m/V ⇒ V=m/ρ V=102,5/7,98=12,84
Now using formula for calculating average density(avg.ρ= m1+m2/V1+V2) I get that 7,98=m1+m2/12,84. Now 102,5=m1+m2 ⇒m1=102,5-m2 so I place this into the formula.
7,98=(102,5-m2)+m2/12,84 but now -m2 and +m2 cancel each other off and I can't seem to find what to do now. Can you please help?
 
Physics news on Phys.org
  • #2
Write an equation for total volume.
 
  • Like
Likes BiGyElLoWhAt
  • #3
Well you can redily find the volume, and you are given the weight. You know that the weight of the gold plus the weight of the quartz = total weight and that the volume of the gold plus volume of the quartz = total volume. 2 equations 2 unknowns.
 
  • #4
Bystander said:
Write an equation for total volume.
Vtotal=Vquartz+Vgold
 
  • #5
And ---- Vquartz = what? And VGold?
 
  • #6
Bystander said:
And ---- Vquartz = what? And VGold?
Well I know that total volume is 12,84cm3 so 12,84cm3=Vquartz+Vgold so Vquartz=12,84cm3 -Vgold and Vgold=12,84cm3 -Vquartz but I really don't know where to move from here because using one of those in my formula I would run into the same problem as with when I would replace mass.
 
  • #7
Oh, my bad, I thought those two equations would be linearly independent for some reason, and also apparently didn't read your attempt at the solution closely enough.
 
  • #8
Arcany said:

Homework Statement


Piece of quartz containing gold weights 102,5g and average density is 7,98g/cm3. Density of quartz is 2,65g/cm3. How much does gold weight?

Homework Equations


ρ=m/V
avg.ρ= m1+m2/V1+V2

The Attempt at a Solution


Using average density I find that volume of this piece is 12,84cm3. ρ=m/V ⇒ V=m/ρ V=102,5/7,98=12,84
Now using formula for calculating average density(avg.ρ= m1+m2/V1+V2) I get that 7,98=m1+m2/12,84. Now 102,5=m1+m2 ⇒m1=102,5-m2 so I place this into the formula.
7,98=(102,5-m2)+m2/12,84 but now -m2 and +m2 cancel each other off and I can't seem to find what to do now. Can you please help?

Are you sure that the problem does not give you the density of gold? Are you allowed to use a handbook to look up the density of gold?

I believe that you do not have enough data with what you have presented. [The data above (total mass, density of quartz, density of sample) can be rewritten to get three equations with four unknowns (two masses and two volumes)]

Another way of thinking about the problem:

Imagine that you have a graph of average density as a function of percent composition of gold. At the left is the density of 100% quartz, at the right is the denisty of 100% gold. You will get a line going from one side to the next (assuming no funny 'mixing' behavior). The problem is that you don't know the right endpoint (i.e. the density of 100% gold), so you don't know what composition corresponds to 7.98 g/cm^3.

For example, suppose that density of gold is 7.98 g/cm^3 (its not, but just suppose). You know then that the sample is 100% gold (if there were any quartz, you would have a lower density). So the mass of gold is 102.5 g.
 
  • #9
Quantum Defect said:
you do not have enough data with what you have presented.
True, but there is enough information to get a lower bound for the answer, and assuming gold is far more dense than quartz it might not be far off.
 
  • #10
haruspex said:
True, but there is enough information to get a lower bound for the answer, and assuming gold is far more dense than quartz it might not be far off.

I do not think so. What lower bound do you get? What assumptions did you make for the density of gold?

(1) mgold + mquartz = Mtotal

(2) Vgold * rho_gold + Vquartz * rho_quartz = Vtotal * rho_ave

Divide both sides of (2) by Vtotal, and you get an equation for the average density (rho_ave) as a weighted average (by volume fraction) of the densities of the two components. If you plot density versus composition (e.g. volume fraction of gold) you get a straight line. Left side y-intercept (0% Au) = density of quartz; right side y-intercept (100% Au) = density of gold. Without knowing what the right side y-intercept is, you cannot calculate a composition for the quoted average density. You can solve for everything in (2), given the information above, except one of the volumes and rho_gold -- one equation, two unknowns.
 
  • #11
Quantum Defect said:
I do not think so. What lower bound do you get?
We are told
Arcany said:
Piece of quartz containing gold ... average density is 7,98g/cm3. Density of quartz is 2,65g/cm3.
If the gold content is zero those two densities conflict. The lower bound is had by assuming the gold is infinitely dense.
 
  • #12
haruspex said:
We are told

If the gold content is zero those two densities conflict. The lower bound is had by assuming the gold is infinitely dense.

No. If gold is infinitely dense, a trace amount of gold (essentially zero fraction) could easily give you the observed density, no? Look at the equation above in #10. Observed density is a weighted average of the individual densities.

Rho_total = rho_quartz * (1-fraction gold) + rho_gold* (fraction gold)

For a very large density of gold (i.e. very little gold)

(Rho_total-rho_quartz ) = rho_gold*fraction gold (fraction gold << 1)

The fraction gold can be made arbitrarily small, no?
 
  • #13
Quantum Defect said:
No. If gold is infinitely dense, a trace amount of gold (essentially zero fraction) could easily give you the observed density, no? Look at the equation above in #10. Observed density is a weighted average of the individual densities.

Rho_total = rho_quartz * (1-fraction gold) + rho_gold* (fraction gold)

For a very large density of gold (i.e. very little gold)

(Rho_total-rho_quartz ) = rho_gold*fraction gold (fraction gold << 1)

The fraction gold can be made arbitrarily small, no?
Define fraction - is that by weight or by volume?
If the gold is infinitely dense it occupies no volume. vol quartz = total vol = total mass / avg density.
mass quartz = (total mass / avg density) * density quartz
mass gold = total mass - mass quartz
 
  • #14
haruspex said:
Define fraction - is that by weight or by volume?
If the gold is infinitely dense it occupies no volume. vol quartz = total vol = total mass / avg density.
mass quartz = (total mass / avg density) * density quartz
mass gold = total mass - mass quartz

"Define fraction -" Defined in #10, above, it is fraction by volume.

From # 12: (Rho_total-rho_quartz ) = rho_gold*fraction gold (fraction gold << 1)
Putting in numbers:
(7.98-2.65) g/cm^3 = rho gold * fraction gold (where fraction gold <<1)

5.33 = rho gold * fraction gold

If fraction gold = 0.01, rho_gold= 533 g/cm^3
If fraction gold = 0.001, rho gold = 5,330 g/cm^3
If rho_gold = "infinity" as you state, fraction gold is "0"

There is no lower bound to the fraction of gold, based upon the math.
 
  • #15
Quantum Defect said:
"Define fraction -" Defined in #10, above, it is fraction by volume.

From # 12: (Rho_total-rho_quartz ) = rho_gold*fraction gold (fraction gold << 1)
Putting in numbers:
(7.98-2.65) g/cm^3 = rho gold * fraction gold (where fraction gold <<1)

5.33 = rho gold * fraction gold

If fraction gold = 0.01, rho_gold= 533 g/cm^3
If fraction gold = 0.001, rho gold = 5,330 g/cm^3
If rho_gold = "infinity" as you state, fraction gold is "0"

There is no lower bound to the fraction of gold, based upon the math.
Yes, there's no lower bound on the volume. But the questions asks for weight (mass), not volume, and there is a lower bound on that.
 
  • #16
haruspex said:
Yes, there's no lower bound on the volume. But the questions asks for weight (mass), not volume, and there is a lower bound on that.
Aha, I see the error of my ways... sorry for being dense ;)
 
  • #17
Quantum Defect said:
Aha, I see the error of my ways... sorry for being dense ;)
No problem. You get high marks from me for acknowledging your agreement. Many just go quiet.
 

1. What is a piece of quartz mixed with gold?

A piece of quartz mixed with gold is a naturally occurring mineral specimen that contains both quartz and gold in its composition. It is often found in areas where there has been volcanic activity or in quartz veins.

2. How is a piece of quartz mixed with gold formed?

A piece of quartz mixed with gold is formed through a process called hydrothermal alteration. This occurs when hot fluids from a magma chamber or other heat source come into contact with pre-existing rocks, resulting in the formation of new minerals such as quartz and gold.

3. Is a piece of quartz mixed with gold valuable?

Yes, a piece of quartz mixed with gold can be valuable depending on the quantity and quality of the gold present. In some cases, gold can be found in large enough quantities to make the specimen worth mining and extracting the gold for commercial use.

4. How can you identify a piece of quartz mixed with gold?

A piece of quartz mixed with gold can be identified by its physical characteristics. It will have a white or clear color with visible gold flakes or veins running through it. It also has a high density and is heavier than most other rocks and minerals.

5. Can a piece of quartz mixed with gold be used for anything?

A piece of quartz mixed with gold has various uses. It is often used as a decorative piece or in jewelry making. It can also be crushed and used in the production of glass, ceramics, and electronics due to its high thermal and electrical conductivity properties.

Similar threads

  • Introductory Physics Homework Help
Replies
20
Views
2K
  • Introductory Physics Homework Help
Replies
4
Views
1K
  • Introductory Physics Homework Help
Replies
20
Views
2K
  • Introductory Physics Homework Help
Replies
32
Views
4K
  • Introductory Physics Homework Help
Replies
3
Views
1K
  • Introductory Physics Homework Help
Replies
5
Views
10K
  • Introductory Physics Homework Help
2
Replies
50
Views
6K
  • Introductory Physics Homework Help
Replies
1
Views
1K
  • Introductory Physics Homework Help
Replies
10
Views
3K
  • Introductory Physics Homework Help
Replies
4
Views
4K
Back
Top