# Find Work done by block of gold?

1. Nov 14, 2012

### studyhard

1. The problem statement, all variables and given/known data
The density of solid gold at 20°C is
ρ = 19.3 g/cm3.
When it is liquid at 1064°C the density of the liquid state is decreased: 17.3 g/cm3. How much work does a block of gold of mass 407 kg do if it is heated at
p = 1.0 atm
from 20°C to 1064°C?

2. Relevant equations
density=mass/volume
PV=nRT
W=-pdeltaV

3. The attempt at a solution
I started by taking difference between two pressures =2.0g/cm3 and then converted that to 2000kg/cm3. with this i used
p=m/v
v=m/p
v=407kg/2000kg/m3
v=0.2035m3 =203.5L
W=-pdeltaV
W=1.0atm(203.5L)
W= 203.5atm.L=20619 J
this does not seem correct at all and it isn't.
1. The problem statement, all variables and given/known data

2. Relevant equations

3. The attempt at a solution

2. Nov 14, 2012

### CWatters

I believe you haven't worked out ΔV correctly. Start by working out the volume at the two different temperatures. Perhaps best to convert the data given in the question to kg and kg/m3 first.