Find Work done by block of gold?

[studyhard]

Homework Statement

The density of solid gold at 20°C is
ρ = 19.3 g/cm3.
When it is liquid at 1064°C the density of the liquid state is decreased: 17.3 g/cm3. How much work does a block of gold of mass 407 kg do if it is heated at
p = 1.0 atm
from 20°C to 1064°C?

Homework Equations

density=mass/volume
PV=nRT
W=-pdeltaV

The Attempt at a Solution

I started by taking difference between two pressures =2.0g/cm3 and then converted that to 2000kg/cm3. with this i used
p=m/v
v=m/p
v=407kg/2000kg/m3
v=0.2035m3 =203.5L
W=-pdeltaV
W=1.0atm(203.5L)
W= 203.5atm.L=20619 J
this does not seem correct at all and it isn't.

 

[CWatters]

I believe you haven't worked out ΔV correctly. Start by working out the volume at the two different temperatures. Perhaps best to convert the data given in the question to kg and kg/m³ first.