Well, the electric field inside the conductor is going to be zero. The field at the surface of the conductor, where the charges are, can be found by Gauss' law. The force on the surface charge will be the electric field at the surface multiplied by the charge, so the force density will be the charge density times the electric field. This will put the conductor under stress.
You'd need some material properties of the conductor to solve the for the distribution of stress. You might do using a non GR approach, but you could also do it using the equation ##\nabla_a T^{ab} = 0##. In general I would expect the division of the stress terms between radial tension and circumfrential tension would depend on the details of the material properties of the conductor, though I haven't attempted any serious analysis.
Weak field approximations would ignore the stress terms anyway, so there's no real reason to calculate them if you're doing a weak field analysis. But it's still not clear if that's what you're doing.
As I mentioned before, known materials can probably not support gravitationally significant tensions and pressures, but for such a case, I see no real need to use GR to analyze your problem. Newtonian physics should be good enough.
You'll also have to consider the exterior electric field as a source of the stress energy tensor, and hence gravitation. This will be a small effect, but it might be a reason to do a full GR analysis. Wiki has the formula for the stress-energy tensor of an electrromagnetic field , see
https://en.wikipedia.org/w/index.php?title=Electromagnetic_stress–energy_tensor&oldid=1028734167. But it'll probably take some specialized knowledge to solve it.