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Placement of an object and magnification

  • Thread starter Violagirl
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  • #1
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Homework Statement



An object is 1 m from a screen. At what points may a 0.05-m focal length lens be placed so as to produce a sharp image on the screen? What are the corresponding magnifications?

Homework Equations



Lens maker equation:

1/s + 1/s' = 1/f

Magnification equation:

m = -s'/s = -f/s


The Attempt at a Solution



For the first question:

1/s' = 1/f -1/s = 1/0.05 m-1 = -.95 m.

1 m - .95 m = 0.05 m away from the screen.

Magnification:

m = -0.05 m / 1 m = -0.05

Is this right?
 

Answers and Replies

  • #2
Use the fact that the sum of the object and image distances is 100 cm.
 

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