Plancherel's Identity proof - justifying order of integration?

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SUMMARY

The discussion centers on justifying the change of integration in the proof of Plancherel's identity under the assumption that \( f(x) \in L^1(\mathbb{R}) \cap L^2(\mathbb{R}) \). The user seeks clarity on the boundedness of the integral of \( |\hat{f}(\xi)| \) in \( L^1 \) to apply Fubini's theorem effectively. It is established that if \( f(x) \) is in \( L^2 \), then the integral \( \int f(\xi) \, \mathrm{d}\xi \) is indeed bounded, which supports the validity of the integration interchange. The discussion highlights the necessity of understanding function spaces and the convolution theorem for a comprehensive proof.

PREREQUISITES
  • Understanding of Plancherel's identity
  • Fubini's theorem application in integration
  • Knowledge of function spaces, specifically \( L^1 \) and \( L^2 \)
  • Fourier transform properties and their implications
NEXT STEPS
  • Study the implications of Fubini's theorem in the context of Fourier transforms
  • Explore the convolution theorem and its application in proving Plancherel's identity
  • Review properties of \( L^1 \) and \( L^2 \) spaces in functional analysis
  • Investigate boundedness of Fourier transforms for functions in \( L^2 \)
USEFUL FOR

Mathematicians, graduate students in analysis, and anyone studying Fourier analysis and functional spaces will benefit from this discussion.

GregA
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With the assumption f(x)\in L^1(\mathbb{R})\cap L^2(\mathbb{R}) (in a Lebesque sense) I'm trying to include a short proof of Plancherel's identity into my dissertation but am having trouble justifying the change of integration at the end of the following line:

<br /> \int_{\mathbb{R}}|f(x)|^2\, \mathrm{d}x<br /> =\int_{\mathbb{R}}f(x)\overline{f(x)}\mathrm{d}x=\int_{\mathbb{R}}f(x)\left [\frac{1}{\sqrt{2\pi}}\int_{\mathbb{R}}\overline{{\hat{f}(\xi)e^{ix\xi}}}\mathrm{d}\xi\right ]\mathrm{d}x<br />

I am aware of Fubini's theorem but my problem is that I can't see why the integral of \left |\hat{f}(\xi)\right | is necessarily bounded in L^1 so that I can use it. [EDIT] Am I allowed to say that since I know f(x)\in L^2 then the equalitities give that \int f(\xi)\mathrm\,{d}\xi is bounded?

A number of texts just swap \mathrm{d}x and \mathrm{d}\xi without worrying this, whilst others just give a hand wavy argument that it all works out ok.

I know that it can be proved using the convolution theorem but the argument is longer. Am I missing something obvious or would anybody be able to point me in the right direction for resolving this problem? (and I acknowledge I have gaps in my knowledge about function spaces etc...)
 
Last edited:
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If f(x) is in L1, its Fourier transform is bounded.
 

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