A man with a mass of 100kg is standing on a uniform plank of mass 50kg. The man is standing directly above the right support and the left support is located at the left end of the plank. The right support is 2m from the right end. the plank is 60m long. What is the magnitude of force the left support applies to the plank, the magnitude of force the right support applies, and if the man's mass was doubled the force by the left support would remain the same, increase or decreas? Equations: Tnet=0 Fnet=0 I tried solving the force by the left support....I set the pivot point on the right support. I got the distance of the man from the pivot point is 0. the beam is 6m long so the center mass is mg(1/2* 6) my equation is tnet=0 I get 100(9.8)(0m)+50(9.8)(3m)-Force left(4m)=0. I know this isnt right but can somone point me in the right direction?