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Please can you help me transpose this problem?

  1. Dec 4, 2011 #1
    7.0588 = sin(10.4*∏*t)

    how do i transpose this to solve the equation finding a value for t?

    thanks
     
  2. jcsd
  3. Dec 4, 2011 #2
    invsin(7.0588) gives (10.4*∏*t)
     
  4. Dec 4, 2011 #3
    invsin(7.0588) in my casio gives a math error
     
  5. Dec 4, 2011 #4
    your casio is ok because the sin of ANY angle must not be greater than 1.
     
  6. Dec 4, 2011 #5
    hmmm here is the full problem, i thought i could solve it with the first question. could you help me more here grzz?

    X=a*Sin(omega*t)

    where x = 0.6m
    a = 0.085m
    omega = 10.4*Pi

    0.6=0.085*Sin(10.4*Pi*t)

    any ideas mate?
     
  7. Dec 4, 2011 #6

    micromass

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    Mod note: moved to Homework forums.

    acat, please make your own attempts to solve the problem. We will not solve it for you.
     
  8. Dec 4, 2011 #7

    eumyang

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    Actually, no, what you posted wasn't the full problem. Why is x = 0.6 m? Why is a = 0.085 m? What situation does this equation model? You need to post the entire word problem. It's possible you plugged in the wrong values for the variables.
     
  9. Dec 5, 2011 #8
    micromass i wouldnt dream of expecting others to finish homework for me. Im just struggeling with this 1 step of my problem and its really bugging me. Im simply asking for help with this 1 step so id feel confident to go off on my own and finish my problem.

    Anyhow, ill post the problem up later on. thanks
     
  10. Dec 5, 2011 #9

    Ray Vickson

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    The equation you wrote is easy to deal with: it has NO (real) solutions. That is because you are asking to have a value of "sine" that is > 1, and that cannot happen for any real angle.

    However, it does have solutions in the complex plane; one is t = 0.0480769 - 0.080874I, where I = sqrt(-1).

    RGV
     
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