Trying to understand(conceptually) orthogonality

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Homework Help Overview

The discussion revolves around the properties of matrices and vectors in the context of orthogonality, specifically examining the implications of the equation \( A^Ty = 0 \) when \( Ax = b \) has a solution. Participants are exploring the relationships between the row space, null space, and the definitions of the vectors involved.

Discussion Character

  • Conceptual clarification, Assumption checking, Mixed

Approaches and Questions Raised

  • Participants are attempting to understand the significance of the transpose of a matrix and its relationship to orthogonality. Questions are raised about the meaning of \( y^T(x) \) and \( y^T(y) \), and whether these expressions imply any specific properties of the vectors involved.

Discussion Status

There is an active exploration of the implications of the given equations, with some participants questioning the relevance of the transpose and the definitions of the vectors. Guidance has been offered regarding the properties of the null space and row space, but no consensus has been reached on the implications of the orthogonality conditions.

Contextual Notes

Participants express confusion regarding the fundamental properties of the matrices and vectors involved, indicating a potential lack of foundational understanding. There is a request for clarification on the problem statement, suggesting that some details may be missing from the discussion.

Arnoldjavs3
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Homework Statement


if Ax = b has a solution and A^Ty = 0 , is y^T(x) = 0 or y^T(y) =0

Homework Equations

The Attempt at a Solution


I simply do not think i understand the properties to answer this question.

From my understandinging, the transpose of A times y is = 0. This means that A transpose and y(all the members of these two subspaces) are perpendicular. Does this indicate that y is essentially the nullspace of A transpose? A transpose is the rowspace?

Where do I progress on frmo this?

I'd like to add... why is the transpose of these matrices even relevant? I don't understand. Are there properties of the transpose that I'm missing? What are these variables y and x representing? There's just so much here that's confusing me(I'm guessing I don't understand fundamentally)

I know that the row space is orthogonal to the nullspace(and colspace with the left nullspace) how do i use this knowledge to solve this problem?
 
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Do you mean Ax=b has a unique solution?
If it has a unique solution then A is invertible, and hence so is ##A^T##, which allows us to choose between the two alternative answers.

But if we only know that Ax=b has at least one solution, then A may be singular, in which case the question is unanswerable.
 
Yes it has a unique solution.

What good does it knowing that A^T and ax=b is invertible?
 
You are given the equation ##A^Ty=0##. Using the fact that ##A## is invertible, and hence so is ##A^T##, rearrange that equation so that y is alone on one side (ie make y the subject of the equation). Then simplify as much as possible.
 
Well if I were to isolate y from that equation you've stated, wouldn't it just be y = 0? the fact that A is invertible(meaning so is its transpose) confuses me. Why does that help me?
 
They've asked you if ##y^Tx = 0## or ##y^Ty =0##. The answer is yes if either or both is true.
If you can show that ##y=0##, can you then prove that at least one of those two is true?

If so, the answer to the set question is Yes.
 
Arnoldjavs3 said:

Homework Statement


if Ax = b has a solution and A^Ty = 0 , is y^T(x) = 0 or y^T(y) =0
What do y^T(x) and y^T(y) mean?
It would be helpful to state that x and y are vectors in some vector space (such as ##\mathbb{R}^n##?).

Since your question is about orthoganality, there's an inner product lurking about somewhere, so presumably y^T(x) could just as well be written as ##\vec{y} \cdot \vec{x}## and y^T(y) could be written as ##\vec{y} \cdot \vec{y}##
Arnoldjavs3 said:

Homework Equations

The Attempt at a Solution


I simply do not think i understand the properties to answer this question.

From my understandinging, the transpose of A times y is = 0. This means that A transpose and y(all the members of these two subspaces) are perpendicular.
That doesn't make any sense. Two vectors can be perpendicular (or othogonal), but a matrix and a vector aren't things that can be perpendicular to each other.
Arnoldjavs3 said:
Does this indicate that y is essentially the nullspace of A transpose? A transpose is the rowspace?
If ATy = 0, then, yes, y is in the nullspace of AT.
Arnoldjavs3 said:
Where do I progress on frmo this?

I'd like to add... why is the transpose of these matrices even relevant? I don't understand. Are there properties of the transpose that I'm missing? What are these variables y and x representing? There's just so much here that's confusing me(I'm guessing I don't understand fundamentally)

I know that the row space is orthogonal to the nullspace(and colspace with the left nullspace) how do i use this knowledge to solve this problem?
 
Arnoldjavs3 said:

Homework Statement


if Ax = b has a solution and A^Ty = 0 , is y^T(x) = 0 or y^T(y) =0

Homework Equations

The Attempt at a Solution


I simply do not think i understand the properties to answer this question.

From my understandinging, the transpose of A times y is = 0. This means that A transpose and y(all the members of these two subspaces) are perpendicular. Does this indicate that y is essentially the nullspace of A transpose? A transpose is the rowspace?

Where do I progress on frmo this?

I'd like to add... why is the transpose of these matrices even relevant? I don't understand. Are there properties of the transpose that I'm missing? What are these variables y and x representing? There's just so much here that's confusing me(I'm guessing I don't understand fundamentally)

I know that the row space is orthogonal to the nullspace(and colspace with the left nullspace) how do i use this knowledge to solve this problem?
Could you post the problem exactly as given to you? It seems like you're leaving a lot of relevant details out.
 

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