Please check my answers: Combined Circuit

[j doe]

Homework Statement

Homework Equations

The Attempt at a Solution

V_t=30V
I_t=4.3A
R_t=7Ω

V₁=12.9V
V₂=2.15V
V₃=2.15V
V₄=4.3V
V₅=12.9V
V_A=4.3V
V_B=4.3V

I₁=4.3A
I₂=2.15A
I₃=2.15A
I₄=2.15A
I₅=4.3A
I_A=2.15A
I_B=4.3A

R₁=3Ω
R₂=1Ω
R₃=1Ω
R₄=2Ω
R₅=3Ω
R_A=2Ω
R_B=1Ω

Did I break down the problem correctly? And are all these calculations correct?

 

[Guneykan Ozgul]

Yes, it seems correct.

 

[Charles Link]

Homework Statement

Homework Equations

The Attempt at a Solution

V_t=30V
I_t=4.3A
R_t=7Ω

V₁=12.9V
V₂=2.15V
V₃=2.15V
V₄=4.3V
V₅=12.9V
V_A=4.3V
V_B=4.3V

I₁=4.3A
I₂=2.15A
I₃=2.15A
I₄=2.15A
I₅=4.3A
I_A=2.15A
I_B=4.3A

R₁=3Ω
R₂=1Ω
R₃=1Ω
R₄=2Ω
R₅=3Ω
R_A=2Ω
R_B=1Ω

Did I break down the problem correctly? And are all these calculations correct?

It looks reasonably good, but electrical currents do have a direction=normally you mark the direction with an arrow and if the current goes opposite to the arrow, it is then a negative current. Also, the voltages you have are voltage drops across the resistors. Often the question will be what is the voltage at a point in the circuit, and in order to do this, a point in the circuit (e.g. the "-" terminal of the voltage source) will be designated as the "V=0" or "ground" point. Then the "+" terminal of the battery will be V=+30 V, and the voltages at other locations are determined from the voltage drops. All in all, you did reasonably good.