Circuit with 2 Batteries and 6 Resistors

  • Thread starter kjlchem
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  • #1
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Homework Statement



A circuit is constructed with six resistors and two batteries as shown. The battery voltages are V1 = 18 V and V2 = 12 V. The positive terminals are indicated with a + sign, The values for the resistors are: R1 = R5 = 56 Ω, R2 = R6 = 157 Ω R3 = 118 Ω, and R4 = 97 Ω. The positive directions for the currents I1, I2 and I3 are indicated by the directions of the arrows. What is V4?

Homework Equations



V=IR

The Attempt at a Solution



I have been trying to apply Kirchoff's laws for junctions and loops.

I picked 2 loops and got the following equations-

I4R4 +I6R6 = V2

R5I5 + R4I4 + R6I6 + R2I2 + R3I3 = V1

From the junction rule, I got that I1 + I3 = I5 = I2

I'm not sure if this is right though- I5 = I2 = I4 = I6

I don't know what to do next. I think I need another equation.
 

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Answers and Replies

  • #2
gneill
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I think you need to step back from the analysis for a moment and ask yourself, "what is determining the voltage across resistors R4 and R5?"
 
  • #3
vela
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Your picture is so small it's illegible. Can you post a bigger version?
 
  • #4
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Your picture is so small it's illegible. Can you post a bigger version?

If you click on it, I think it gets bigger.
 
  • #5
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Okay, I got that part. Now, to find I3, can I use my equations and Kirchoff's laws?
 
  • #6
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Never mind! Got it! The problem also asks for the potential difference between V(a) and V(b).

Is this just V=IR where R= R6 and I=I2?
 
  • #7
vela
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Yes, that's right.
 
  • #8
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How'd you figure out I3?
 

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