The difference is in the directions. Voltage drop is numerically equal to the back emf of the inductor. Their directions are opposite. If voltage across inductor is 5V at a particular instant, that means 5V from the source are dropped across the inductor and its back emf at that instant is 5V.Clara Chung said:
Yes.andrevdh said:
As cnh1995 pointed out, a practical inductor can be modeled as an ideal inductance in series with a resistance. So when you measure voltage across the terminals of a practical inductor you are measuring the sum of two voltages: voltage due to inductance, ##\color{blue}{L\dfrac{di}{dt}}## + Ohmic drop, ##\color{blue}{i{\cdot}R}##.Clara Chung said:
Voltage is a measure of the electric potential energy per unit charge in an electric field. It is commonly referred to as the electrical force that drives the flow of electrons through a circuit.
Voltage is calculated by dividing the energy used or released in a circuit by the amount of charge that is flowing through the circuit. It is represented by the symbol V and measured in volts (V).
The formula for voltage is V = W/Q, where V is voltage, W is the energy used or released in the circuit, and Q is the amount of charge flowing through the circuit. This formula is known as Ohm's law.
Voltage is measured in volts (V), which is equivalent to joules per coulomb (J/C). Other common units for voltage include millivolts (mV), kilovolts (kV), and megavolts (MV).
Voltage plays a crucial role in determining the performance and functionality of electronic devices. Too little or too much voltage can damage or even destroy electronic components. Devices are designed to operate within a specific voltage range, and exceeding this range can cause malfunctions or failures.
