Solving Inductor Circuit Homework Problems

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The discussion revolves around solving a circuit problem involving inductors and resistors. Participants clarify that immediately after closing the switch, the inductor behaves like an open circuit, resulting in no current through the 60.0-Ω resistor. They also establish that the potential difference across the 15.0-mH inductor equals that across the 60.0-Ω resistor at that moment. After a long time with the switch closed, the inductor acts as a short circuit, leading to zero voltage across the 60.0-Ω resistor due to the current stabilizing. Overall, the circuit behavior is analyzed using Ohm's law and the properties of inductors in steady-state conditions.
  • #51
cnh1995 said:
Yes.

I don't know what you mean by that. If the middle wire were not there, the current would flow through both the 30 and 60 ohm reistors. But since they are in parallel with the middle wire, no current flows in either of them. Look up 'current divider'.
hmm ok so now since the 30 and 60 ohm resistors are in parallel, they would be in parallel with the 40 mH inductor that is now a straight wire. the 40 mH inductor will have 0 potential difference so since it is in parallel with the 30 and 60 ohms resistors the 60 ohm resistor will have the potential difference of 0.

So i guess somewhat in the end the circuit should just have the voltage, and 10 ohm resistor?
 
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  • #52
superslow991 said:
So i guess somewhat in the end the circuit should just have the voltage, and 10 ohm resistor?
Right.
 
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  • #53
cnh1995 said:
Right.
Ok thanks a lot man
 

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