Please verify my answer to this question about the domain

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Homework Statement
Find the natural domain of the function ln composed with itself n times.
Relevant Equations
ln(x) is defined only for x>0.
For n=1 (ln(ln(x))), the domain is the set of all real x>1 ;
for n=2, the domain is the set of all real x>e ;
for n=3, the domain is the set of all real x>e^e ;
for n=4, the domain is the set of all real x>e^(e^e)
...Thus, for a general n the domain is the set of all real x greater than e^(e^...^e^e) ,where there are n-2 terms in the parentheses.
(Sorry if this is confusing, I'm still trying to figure out LATEX.)
 
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You should first figure out from where to where the logarithm goes: from to get the original domain, to because these are the domains of the iterations. Which values can you feed the logarithm with?

Then try to figure out what ##\log^n(x)## does.

And by the way, ##\log^1(x)=\log(x)##.

Here is explained how you can type formulas on PF: https://www.physicsforums.com/help/latexhelp/
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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