Plotting f (x, y) = ln(x^2 + y^2 ) - Mathematica Help

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To plot the function f(x, y) = ln(x^2 + y^2) in Mathematica, users can utilize the Plot3D command with the syntax Plot3D[Log[x^2 + y^2], {x, xmin, xmax}, {y, ymin, ymax}]. For symmetry in both x and y axes, it is recommended to set xmin equal to ymin and xmax equal to ymax. Additionally, users can define the function as f[x_, y_] = Log[x^2 + y^2] and then plot it using Plot3D[f[x, y], {x, xmin, xmax}, {y, ymin, ymax}]. To achieve a cylindrical coordinate representation, the ParametricPlot3D command can be used. Properly configuring these commands allows for accurate three-dimensional visualizations of the function.
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I'm trying to plot this
f (x, y) = ln(x^2 + y^2 )

any one got a idea how to?
 
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Plot3D[f, {x, xmin, xmax}, {y, ymin, ymax}]
make a three-dimensional plot of f as a function of the
variables x and y
 
More accurately,

Plot3D[Log[x^2 + y^2], {x, xmin, xmax}, {y, ymin, ymax}]

or

f[x_,y_]=Log[x^2 + y^2]
Plot3D[f[x,y], {x, xmin, xmax}, {y, ymin, ymax}]
 
i want to make this symmetric in both x and y with 2 graph by using the cartesian coordinate system with the plot3D command and secondly using the cyclindrical coordinate system using the parametricplot3d command. been a long time since I've used mathematica but i don't think your codes does the above right?
 
anyone ?
 

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