Plotting isoclines corresponding to slopes m = +1 and m -1?

1. Aug 21, 2013

Given the first order ODE y' = 2 * y^3 * x, plot the isoclines corresponding to slopes m = +1 and m = -1.

The isoclines are given by m= 2 * y^3 * x or y=(m/(2*x))^1/3

The slope elements on the isocline y=+- (m/(2*x))^1/3 all have gradient m

For m = 1, the isocline is y = +- (1/(2*x))^1/3
For m = -1, the isocline is y = +- (-1/(2*x))^1/3

and hence l simply plotted the above two equations

Can anyone confirm whether or not l am correct

Thanks

2. Aug 21, 2013

Natr0n

Seems correct except in
You don't need $\pm$ because you're taking the cube root not the square root.