Plummer Sphere, Density from Potential

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SHISHKABOB
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Homework Statement


It wants me to get the density function of a Plummer sphere from its gravitational potential.


Homework Equations


Plummer sphere potential:

[itex]\Phi (r) = -\frac{GM}{\sqrt{r^{2}+a^{2}}}[/itex]

where phi is the potential as a function of radius from the mass, M. And a is a scale factor of the model. I think I'm just supposed to take M as a constant here.

I am supposed to end up with

[itex]\rho = \frac{3a^{2}}{4\pi}\frac{M}{(r^{2} + a^{2})^{5/2}}[/itex]


The Attempt at a Solution



So according to Poisson's equation

[itex]\nabla ^{2} \Phi = 4\pi G \rho (x)[/itex]

So to solve for ρ I just took the derivative of Phi twice with respect to r twice and then divided by 4πG

first derivative got me

[itex]2rGM(r^{2} + a^{2})^{-1/2}[/itex]

and then the second derivative got me

[itex]\frac{GM}{2}\left[2(r^{2} + a^{2})^{-3/2} - (r^{2} + a^{2})^{-1/2}\right][/itex]


then after a bit of rearranging I have ended up with

[itex]\frac{M}{8\pi}(r^{2} + a^{2})^{-1/2}(2 - \frac{1}{r^{2} + a^{2}})[/itex]

I'm not really sure if I'm on the right track...
 
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The Laplacian is not "taking the derivative with respect to r twice". Look up its expression in spherical coordinates (or derive it, if you are not supposed to know).
 
voko said:
The Laplacian is not "taking the derivative with respect to r twice". Look up its expression in spherical coordinates (or derive it, if you are not supposed to know).

ohhh yes you are right, thank you. That explains a lot :redface: