Pobability pmf of 1 thing is greater than another* help needed*

  • Thread starter Thread starter cloud360
  • Start date Start date
Click For Summary
SUMMARY

The discussion focuses on calculating the probability mass function (PMF) for the outcome of a dice game in Risk, where the red army rolls three dice and the blue army rolls two. The red army wins if it rolls a higher number than the blue army, with ties favoring the blue army. The user seeks assistance in determining the probability that the red army wins, utilizing concepts such as cumulative distribution functions (CDF) and PMF calculations. The user proposes a relationship between the PMFs of the two armies, indicating a need for clarification on the correct approach to solving the problem.

PREREQUISITES
  • Understanding of probability mass functions (PMF)
  • Knowledge of cumulative distribution functions (CDF)
  • Familiarity with basic probability concepts in games of chance
  • Experience with combinatorial calculations involving dice
NEXT STEPS
  • Study the calculation of PMFs in discrete probability distributions
  • Learn how to derive probabilities in multi-dice scenarios
  • Explore the concept of expected value in games of chance
  • Review the rules and strategies of the game Risk for better context
USEFUL FOR

Students studying probability theory, game theorists, and anyone interested in applying statistical methods to game outcomes.

cloud360
Messages
212
Reaction score
0
Pobability pmf of 1 thing is greater than another*urgent help needed*

Homework Statement



In the game of Risk, battles are decided by the rolling of dice. Suppose that there are two armies,
red and blue. The red army rolls three dice and the blue army rolls two dice. Whichever army rolls
the highest number (on a single die) is declared the winner. In the event of a tie (both armies have
the same highest number), the blue army is declared the winner.

(c) Calculate the probability that the red army wins.

Homework Equations



cdf=cumulative distribution function=p(x<=X)

The Attempt at a Solution


I don't know how to do last question. But i have this info to answer it.i collected this info by answering question 1 + 2 which i have not included here.


[PLAIN]http://img233.imageshack.us/img233/8079/pmfdf.gif
 
Last edited by a moderator:
Physics news on Phys.org


anyone
 


i think we let x=k

pmf a> pmf b

let pmf a = p(x=k)
pmf b=p(x=k-1)

then pmf a * pmf b = p(x=k)*p(x=k-1).....is this correct
 

Similar threads

Replies
10
Views
3K
Replies
1
Views
2K
  • · Replies 18 ·
Replies
18
Views
4K
  • · Replies 19 ·
Replies
19
Views
7K