Calculating the Probability of Winning in Risk: A Closed-Form Solution

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SUMMARY

The discussion focuses on calculating the probability of winning in the game of Risk using a closed-form solution. The rules dictate that attackers can roll up to 3 dice and defenders up to 2 dice, with outcomes determined by comparing the highest rolls. The user seeks to express the function f(n)ij in closed form, referencing a report that outlines the probabilities of outcomes and the necessary transition probability constants. The goal is to derive the final expressions for the probability of winning and expected army losses based on the number of attacking (A) and defending (D) armies.

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  • Understanding of probability theory and combinatorial analysis
  • Familiarity with the game mechanics of Risk
  • Knowledge of closed-form solutions in mathematical expressions
  • Ability to interpret mathematical notation and functions
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  • Research closed-form solutions in probability theory
  • Study the transition probability constants as outlined on page 4 of the referenced report
  • Examine the derivation of f(n)ij and its implications for game strategy
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Homework Statement


In a game of Risk, the rules are:

The rules for determining how many dice a player may roll:

1. The attacker may roll as many dice as the number of attacking pieces he is using, to a maximum of 3. If A>3, the attacker continues to roll 3 dice per turn.
2. The defender may roll as many dice as the number of armies on his country, to a maximum of 2. If D>2, the defender continues to roll 2 dice per turn.

The rules for deciding the outcome of a particular throw of the dice are as follows:

1. The highest attacker die is compared against the highest defender die. Whoever has the lower number loses one army. Ties go to the defender.
2. The procedure is repeated for the second-highest dice, where both attackers and defenders have a second die.

If you attack a territory defended by D armies with A armies, what is the probability that you will capture this territory? In such a scenario, how many armies should you expect to lose (whichever side that will prevail)?

2. Other relevant info

Previously I had thought we needed a recursive solution, and reached one with the help of some members on this forum. But now I wonder if a closed-form solution is possible. Take a look at this report: http://web.archive.org/web/20060919204627/http://www4.stat.ncsu.edu/~jaosborn/research/RISK.pdf. As noted on page 2, A is the number of attacking armies and D is the number of defending armies.

First of all, the probabilities of each outcome on a certain turn are given on page 5. We don't need to worry about that. What really interests us is the section entitled "The Probability of Winning a Battle", and what comes after that (pages 4 onwards).

How do we express the function f(n)ij, found at the bottom of page 4, in closed form, in terms of the values of n, i and j? If we can figure this out, then, as noted half-way down page 5, fij is simply the sum of f(n)ij from n=1 to n=∞. And then, at the bottom of page 5, we perform a summation across all values of j. i=A*D apparently, or perhaps I am interpreting that wrong?

Anyway, if someone can give me help on how to reach the final 2 expressions on the bottom of page 5 in closed-form, that would be a great start.
 
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Another PDF I have found which may offer some solutions is attached, but personally I find it even more confusing.

Edit: I should have noted above that where I said I want a closed-form solution in terms of the values of n, i and j, what I meant was a closed-form solution in terms of n, i, j and the transition probability constants listed on page 4, which I would prefer kept algebraic.
 

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