Pocklington's Criterion: A Closer Look

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SUMMARY

The discussion centers on Pocklington's Criterion, specifically addressing confusion regarding its conditions as stated on MathWorld. The user examines the theorem using the example of p=3 and k=4, highlighting that the GCD conditions and the requirement that N divides a^(kp)+1 are crucial for the theorem's application. The user references Ribenboim's "My Numbers, My Friends" to clarify the missing conditions that are essential for correctly applying the theorem. This indicates that the MathWorld explanation is incomplete and potentially misleading.

PREREQUISITES
  • Understanding of prime numbers and their properties.
  • Familiarity with the concept of GCD (Greatest Common Divisor).
  • Knowledge of modular arithmetic and its applications.
  • Acquaintance with number theory, specifically Pocklington's Criterion.
NEXT STEPS
  • Study the complete statement and proof of Pocklington's Criterion.
  • Explore Ribenboim's "My Numbers, My Friends" for deeper insights into number theory.
  • Learn about the implications of GCD in number theory and its applications in primality testing.
  • Investigate other primality tests and their conditions for comparison with Pocklington's Criterion.
USEFUL FOR

Mathematicians, number theorists, and students studying advanced topics in prime number theory will benefit from this discussion, particularly those interested in the nuances of Pocklington's Criterion and its applications.

CRGreathouse
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http://mathworld.wolfram.com/PocklingtonsCriterion.html

I'm confused by the statement of this theorem. Either there's a mistake in the explanation, or I'm missing something pretty big.

Let me take an example and go through step by step. Let p=3 and k=4. p is an odd prime and 1 <= 4 <= 8. 3 does not divide 4.

The statement on MathWorld seems to say that 1 and 2 are equivilent:
1. 25 = 2 * 4 * 3 + 1 is prime.
2. There exists an a such that GCD(a^4+1, 25)=1.

5*5=25 is not prime. Checking briefly:
GCD(1,25)=1
GCD(2,25)=1
GCD(17,25)=1
GCD(82,25)=1
GCD(257,25)=1
GCD(626,25)=1

What am I misunderstanding?
 
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Odd, Mathworld seems to leave out a couple of conditions. You also need

2<=a<N

and

N divides a^(kp)+1

for condition 2.

This is in Ribenboim's My Numbers, My Friends.
 
I knew there was something. The entry was overly sparse.

Thanks!
 

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