Point on Graph of Equation....1

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SUMMARY

The discussion confirms that the point (a, 4a) lies on the graph of the equation y = 4x. By substituting x = a into the equation, it is established that y equals 4a, validating the point's position on the graph. The solution demonstrates a straightforward application of algebraic principles to verify point coordinates against a linear equation.

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Determine if the given point lies on the graph of the equation.

(a, 4a); y = 4x

Solution:

Let y = 4a

Let x = a

y = 4x

4a = 4a

Yes, the point (a, 4a) lies on the graph of y = 4x.

Correct?
 
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