For an isotropic material, the relation between the longitudinal ultrasonic(adsbygoogle = window.adsbygoogle || []).push({});

velocity(VL), the transverse (shear) ultrasonic velocity(VT) and the Poisson's ratio (nu) is given by

(VT/VL)^2 = (1-2*nu)/(2*(1-nu))

From the above relation, one gets that VL=0 when nu=1 which is

not physically acceptable as nu varies between -1 and 0.5 for an

isotropic material. On the contrary when nu=0, VT/VL=sqrt(0.5).

However, when nu=0, what happens to the longitudinal ultrasonic

velocity. Does VL becomes zero when nu beccomes zero ?

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# Poisson's Ratio and Ultrasonic Velocity for Isotropic Material

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