Polar coordinate to compute the volume

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SUMMARY

The discussion focuses on using polar coordinates to compute the volume of a region defined by the inequalities 4 - x² - y² ≤ z ≤ 10 - 4x² - 4y². The correct approach involves recognizing that the problem is set in cylindrical coordinates, which include the z-axis, rather than purely polar coordinates. The intersection of the surfaces occurs at r = √2, and the volume element is derived from the area element r dr dθ multiplied by the height difference between the upper and lower surfaces, zupper - zlower.

PREREQUISITES
  • Understanding of cylindrical coordinates and their application in three-dimensional space.
  • Familiarity with volume integration techniques in calculus.
  • Knowledge of polar coordinates and their relationship to cylindrical coordinates.
  • Ability to set up and evaluate multiple integrals.
NEXT STEPS
  • Study the derivation of volume elements in cylindrical coordinates.
  • Learn how to set up triple integrals for different coordinate systems.
  • Explore the relationship between polar and cylindrical coordinates in depth.
  • Practice solving volume problems involving inequalities and multiple integrals.
USEFUL FOR

Students in calculus, particularly those studying multivariable calculus, as well as educators and anyone interested in understanding the application of polar and cylindrical coordinates in volume computation.

DrunkApple
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Homework Statement


Use polar coordinates to compute the volume of the region defined by
4 - x^{2} - y^{2} ≤ z ≤ 10 - 4x^{2} - 4y^{2}


Homework Equations





The Attempt at a Solution


I got z = 2 so set up the equation

V = f^{2pi}_{0}f^{5/2}_{2}f^{0}_{2}r*dzdrdθ

is the domain correct?
 
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DrunkApple said:

Homework Statement


Use polar coordinates to compute the volume of the region defined by
4 - x^{2} - y^{2} ≤ z ≤ 10 - 4x^{2} - 4y^{2}

Homework Equations


The Attempt at a Solution


I got z = 2 so set up the equation

V = f^{2pi}_{0}f^{5/2}_{2}f^{0}_{2}r*dzdrdθ

is the domain correct?
Those are cylindrical coordinates, not polar. (If you were to do the problem in cylindrical coords, your limits of integration for z would be incorrect.)

The two surfaces intersect at z=2, but that's not particularly important. At what value of r do they intersect?
 
setting 4 - x^{2} - y^{2} and 10 - 4x^{2} - 4y^{2} to equal, r = ±√2, but since r must be greater than 0, it's r = √2
 
The volume element is the area element, r dr dθ, times the height, which you get from zupper - zlower .

z goes from 4 - r2 to 10 - 4r2 .
 
thank you I got it.
But how do I know if it's cylindrical?
 
How do you know if what is cylindrical? If you mean the coordinate system, "cylindrical coordinates" are just polar coordinates for the xy-plane with the z coordinate.
 
I mean just by looking at the equation
Is it because it contains z?
 
DrunkApple said:
thank you I got it.
But how do I know if it's cylindrical?
If you're asking how did I know you were using cylindrical coordinates rather than polar; cylindrical coordinates are in 3 dimensions and use r, θ, and z. Polar coordinates are 2 dimensional using r and θ.
 

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