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stolencookie

## Homework Statement

Evaluate the triple integral y^2z^2dv. Where E is bounded by the paraboloid x=1-y^2-z^2 and the place x=0.

## Homework Equations

x=r^2cos(theta) y=r^2sin(theta)

## The Attempt at a Solution

I understand how to find these three limits, -1 to 1 , -sqrt(1-y^2) to sqrt(1-y^2) , 0 to 1-y^2-z^2. I then solved the first integral and got y^2z(1-y^2-z^2) I know I need to convert to polar coordinates. I am able to do that 0 to 2pi, 0 to 1.

I am having trouble converting the equation y^2z(1-y^2-z^2) to polar coordinates.

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