Polymerization of 2-Chloro-2-Butene: Solution

  • Thread starter Thread starter Macroer
  • Start date Start date
  • Tags Tags
    Polymer
Click For Summary
SUMMARY

The discussion focuses on the addition polymerization of 2-chloro-2-butene, detailing the initiation and termination processes involved in polymer formation. The initiator (I) reacts with 2-chloro-2-butene to form a radical, leading to the growth of the polymer chain. The end groups of the polymer are specified as (CH3)(I)C- and (CH3)(Cl)(I)C-, which are crucial for understanding the structure of the final polymer. Participants clarify the importance of accurately representing the end groups in the polymer structure.

PREREQUISITES
  • Understanding of addition polymerization mechanisms
  • Familiarity with radical initiators in polymer chemistry
  • Knowledge of organic chemistry nomenclature and structure representation
  • Experience with drawing polymer structures and end groups
NEXT STEPS
  • Study the mechanism of addition polymerization in detail
  • Learn about different types of radical initiators and their roles
  • Explore the significance of end groups in polymer chemistry
  • Investigate the properties and applications of polymers derived from 2-chloro-2-butene
USEFUL FOR

Chemistry students, organic chemists, and professionals involved in polymer science who are looking to deepen their understanding of polymerization processes and the structural characteristics of polymers.

Macroer
Messages
27
Reaction score
0

Homework Statement


How would the polymer of 2-chloro-2-butene look when formed by addition polymerization


Homework Equations





The Attempt at a Solution


I have attached my solution. Please tell me if i am right/wrong and why if it is wrong.
 

Attachments

  • polymer.JPG
    polymer.JPG
    3.5 KB · Views: 461
Physics news on Phys.org
What does the initiator end of the molecule look like? How is the process terminated? What does the other end of the molecule look like?
 
Initiation:

I* + CH2=CCl-CH2-CH3--> I-CH2-CHCl*-CH2-CH3How is that for initiation step? where I is initiator and * is radical sign
 
You drew 2-chloro-1-butene. How about the 2-butene version? Do you think you will need to show the end groups in your answer? (I honestly don't know)
 
I* + CH3-CCl=CH-CH3--> I-CH2-CCl*-CH2-CH3

And i am not sure what the "end groups" you are referring to are.
 
I* + CH3-CCl=CH-CH3 --> (CH3)(Cl)(I)C-C*(Cl)(CH3) Step 1 (not a polymer yet)

The end groups are (CH3)(Cl)(I)C- in the example above. It will always be at the end of the new polymer, thus 'end group'. What about the other end?
 
I don't understand where you got the 2nd chlorine atom from
 
You're right. Should be...

(CH3)(I)C-C*(Cl)(CH3)

and...

The end groups are (CH3)(I)C- in the example above.
 
Last edited:

Similar threads

  • · Replies 0 ·
Replies
0
Views
2K
  • · Replies 2 ·
Replies
2
Views
2K
Replies
1
Views
2K
Replies
4
Views
4K
  • · Replies 1 ·
Replies
1
Views
2K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 2 ·
Replies
2
Views
3K
  • · Replies 3 ·
Replies
3
Views
4K
  • · Replies 11 ·
Replies
11
Views
3K
Replies
19
Views
4K