Polynomial Equation: Solving for x with 3 Solutions | Math Homework

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The polynomial equation (17-x)2(11-x) + 256 - 32(17-x) - 64(11-x) = 0 has three solutions. The equation can be simplified using substitutions such as u = 17 - x or v = 11 - x, leading to the cubic equations u3 - 6u2 - 96u + 640 = 0 and v3 + 12v2 - 60v + 64 = 0, respectively. The substitution t = 9 - x yields a simpler polynomial for easier computation. This approach is more efficient than direct multiplication of the original equation.

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Homework Statement


Find [tex]x[/tex]
[tex](17-x)^2(11-x)+256-32(17-x)-64(11-x)=0[/tex]


Homework Equations





The Attempt at a Solution


This eq has 3 solutions. I solved this by multiplication. Is this some other easier way. Perhaps to group some of the factors [tex]17-x[/tex] and [tex]11-x[/tex]. Tnx for the answer.
 
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matematikuvol said:

Homework Statement


Find [tex]x[/tex]
[tex](17-x)^2(11-x)+256-32(17-x)-64(11-x)=0[/tex]

Homework Equations



The Attempt at a Solution


This eq has 3 solutions. I solved this by multiplication. Is this some other easier way. Perhaps to group some of the factors [tex]17-x[/tex] and [tex]11-x[/tex]. Tnx for the answer.
I don't know of any particularly easy way. When multiplied out you have some pretty big coefficients and a very large constant term.

Use some substitution. Either of the following is suggested by the problem itself.
[itex]u=17-x[/itex]

[itex]v=11-x[/itex]​
The first takes a little less computation. It results in:
[itex]u^3-6u^2-96u+640=0[/itex]​
The other results in a much smaller constant term.
[itex]v^3+12v^2-60v+64=0[/itex]​

Of course if you use the substitution, [itex]t=9-x\,,[/itex] you get a very simple polynomial.
 

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