Population curve and calculations

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SUMMARY

The discussion focuses on modeling rabbit population growth using differential equations, specifically the equation dP/dt = 0.1P, where P(0) = 1000 represents the initial population. The growth rate of 20% per year is equivalent to a constant k of 0.1 in the differential equation model. Participants are encouraged to derive the general solution to this equation to predict the rabbit population over a specified time frame, such as 10 years.

PREREQUISITES
  • Understanding of differential equations, specifically the exponential growth model.
  • Familiarity with the notation and terminology of population dynamics.
  • Basic knowledge of calculus, particularly integration techniques.
  • Experience with mathematical modeling and population projections.
NEXT STEPS
  • Learn how to solve first-order linear differential equations.
  • Research the implications of different growth rates on population models.
  • Explore applications of the exponential growth model in real-world scenarios.
  • Investigate the effects of carrying capacity on population dynamics.
USEFUL FOR

Mathematicians, biologists, ecologists, and students studying population dynamics or differential equations will benefit from this discussion.

shinobiazra
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Suppose rabbit populations grow exponentially with a growth rate of 20% per year. If P(t) is the population at any time t and 1000 is the initial (t=0) population of rabbits, what is the population of rabbits in 10 years?
Use the DE model: P ' = kP with k = .1 and P(0) = 1000.

Plz help me
 
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Welcome to PF!

Hi shinobiazra! Welcome to PF! :wink:
shinobiazra said:
Use the DE model: P ' = kP with k = .1 and P(0) = 1000.

The equation is dP/dt = 0.1 P …

what is the general solution to this equation? :smile:
 

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