At time t=0 an ant starts to walk from -2f to -f at a constant speed v. Show that the position (q) and velocity (u) of the ants image as a function of time is given by:
q=(2f-vt)f/(f-vt) AND u = f2v/(f-vt)2
d(u/v)/dx = [V(du/dx)-U(dv/dx)]/v2
The Attempt at a Solution
I am finding it hard to start the solution.