the problem is given a(t)=4(t+3)^2, v0=-1, x0=1 find x(t), the position function(adsbygoogle = window.adsbygoogle || []).push({});

to my knowledge x(t)= 1/2at^2+v0t+x0

I tried it and got the wrong answer, the answer the book gives is: 1/3(t+3)^4 - 37t -26

I did:

x(t)= 1/2 [4(t+3)^2)]t^2 - 1t +1

eventually getting: 4t^2 + 24t + 9 for the part in parenthesis

and 2t^4 +12t^2 + 9/2t^2 after multiplying by t^2 and then 1/2

What I'm getting it shaping up to look nothing like the answer, so I know I'm missing something big here.

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# Homework Help: Position function x(t) question

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