Dominathan
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For a function f(x), I have to determine intervals of increase/decrease, find local max(s)/min(s), and find intervals of concavity. The first thing I'm doing in this is to write out f'(x) and f''(x).
f(x) = ln(x)/\sqrt{x}
For f'(x), I used the quotient rule and received f'(x) = ((\frac{1}{x}\sqrt{x})-(\frac{-\sqrt{x}}{2}ln(x))) / 2
However, I plugged f(x) into wolfram alpha and it gave me: \frac{2-ln(x)}{2x^{3/2}}
I don't understand the difference? I thought I had done this correctly but apparently not? Wolfram alpha used the product rule. Is there some kind of algebraic gymnastics I'm forgetting about? I really want to understand where my error was made, not just which is the correct answer. Thanks!
f(x) = ln(x)/\sqrt{x}
For f'(x), I used the quotient rule and received f'(x) = ((\frac{1}{x}\sqrt{x})-(\frac{-\sqrt{x}}{2}ln(x))) / 2
However, I plugged f(x) into wolfram alpha and it gave me: \frac{2-ln(x)}{2x^{3/2}}
I don't understand the difference? I thought I had done this correctly but apparently not? Wolfram alpha used the product rule. Is there some kind of algebraic gymnastics I'm forgetting about? I really want to understand where my error was made, not just which is the correct answer. Thanks!