Possible mistake during differentiation? Please check

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SUMMARY

The discussion focuses on the differentiation of the function f(x) = ln(x)/√x. The user initially applied the quotient rule incorrectly, leading to a discrepancy between their result and the correct derivative provided by Wolfram Alpha, which is (2 - ln(x))/(2x^(3/2)). Key errors included misapplying the derivative of √x and incorrectly handling the denominator in the quotient rule. The correct application of the quotient rule yields the same result as Wolfram Alpha, emphasizing the importance of proper differentiation techniques.

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Dominathan
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For a function f(x), I have to determine intervals of increase/decrease, find local max(s)/min(s), and find intervals of concavity. The first thing I'm doing in this is to write out f'(x) and f''(x).

f(x) = ln(x)/\sqrt{x}

For f'(x), I used the quotient rule and received f'(x) = ((\frac{1}{x}\sqrt{x})-(\frac{-\sqrt{x}}{2}ln(x))) / 2

However, I plugged f(x) into wolfram alpha and it gave me: \frac{2-ln(x)}{2x^{3/2}}

I don't understand the difference? I thought I had done this correctly but apparently not? Wolfram alpha used the product rule. Is there some kind of algebraic gymnastics I'm forgetting about? I really want to understand where my error was made, not just which is the correct answer. Thanks!
 
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In using the quotient rule you are not differentiating \sqrt{x} corretly and the quotient rule requires you to divide by the square of the denominator.
 
Dominathan said:
f(x) = ln(x)/\sqrt{x}

For f'(x), I used the quotient rule and received f'(x) = ((\frac{1}{x}\sqrt{x})-(\frac{-\sqrt{x}}{2}ln(x))) / 2

I see a couple of issues here:

1) How did you get \frac{-\sqrt{x}}{2} in the numerator? What is the derivative of \sqrt{x} ?

2) How did you get 2 in the denominator? (\sqrt{x})^{2} = ?
 
Using quotient rule, you should get \frac{\frac{\sqrt{x}}{x} - \frac{\ln{x}}{2 \sqrt{x}}}{x} which simplifies to what you got from WA. It looks like you messed up on the derivative of \sqrt{x} and on the bottom of the quotient rule. http://en.wikipedia.org/wiki/Quotient_rule
 
gb7nash said:
I see a couple of issues here:

1) How did you get \frac{-\sqrt{x}}{2} in the numerator? What is the derivative of \sqrt{x} ?2) How did you get 2 in the denominator? (\sqrt{x})^{2} = ?

1.
The following is my logic for the answer I received:
  1. \sqrt{x} = x^{1/2}
  2. Using the power rule I bring the 1/2 out as a coefficient, and subtract one from the numerator : \frac{1}{2}x^{-1/2}
  3. I simplified to : \frac{-\sqrt{x}}{2}

2.
My bad! I did a poor job transcribing it from my notebook to the syntax used on this site. It was (obviously) my first post, but far from my last! I meant to put "x" as the denominator, that was a mental slip.
 
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