Potential Difference between earth and battery

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SUMMARY

The discussion centers on the necessity of completing an electrical circuit for a light bulb to function when connected to a battery. Participants emphasize that the negative terminal of the battery must be connected to ground to create a complete circuit, allowing current to flow. Without this connection, even if a potential difference exists, the bulb will not illuminate due to the lack of a closed loop. Key points include the high resistance of air and the importance of ensuring all components are properly connected to avoid circuit interruptions.

PREREQUISITES
  • Understanding of basic electrical circuits
  • Knowledge of potential difference and voltage
  • Familiarity with battery terminals and their functions
  • Awareness of electrical resistance and conductors
NEXT STEPS
  • Research the principles of Ohm's Law and its application in circuits
  • Learn about circuit diagrams and how to represent electrical connections visually
  • Explore the concept of grounding in electrical systems
  • Study the behavior of current flow in series and parallel circuits
USEFUL FOR

Electronics enthusiasts, students learning about electrical circuits, and anyone troubleshooting battery-powered devices will benefit from this discussion.

Elsa1234
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When I connected the positive terminal of the battery to one terminal of the bulb and the other terminal (of the bulb)to the ground the bulb did not glow, even when a potential difference exists?
 
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I don't know what actual circuit you were using but the - on your battery needs to have a continuous connection to Earth. The Earth has to complete the circuit. Check the connections. (Try it with just a negative' wire first, to check battery, bulb and holder.)
 
Elsa1234 said:
When I connected the positive terminal of the battery to one terminal of the bulb and the other terminal to the ground the bulb did not glow, even when a potential difference exists?

Im presuming ( from your description) this is your setup ...

cct.GIF


you have a hole in the circuit ... the other side of the light bulb isn't connected to anything
Yes, there is a potential difference between the other terminal of the light bulb and the ground,
but the air resistance is VERY high ( a very good insulator). The breakdown voltage of air is at least
5000V / cm possibly higher ( someone will confirm)

Dave
 
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davenn said:
Im presuming ( from your description) this is your setup ...

View attachment 88323

you have a hole in the circuit ... the other side of the light bulb isn't connected to anything
Yes, there is a potential difference between the other terminal of the light bulb and the ground,
but the air resistance is VERY high ( a very good insulator). The breakdown voltage of air is at least
5000V / cm possibly higher ( someone will confirm)

Dave
No this is not my circuit , the negative side of the bulb is connected to the ground instead of the negative terminal of the battery
 
Elsa1234 said:
No this is not my circuit , the negative side of the bulb is connected to the ground instead of the negative terminal of the battery
If you don't connect bulb and battery to Earth then how is there a complete circuit`??
Left to its own devices, the positive terminal of the battery will be pulled to Earth potential and the negative terminal will find itself at -battery volts.
 
Elsa1234 said:
When I connected the positive terminal of the battery to one terminal of the bulb and the other terminal (of the bulb)to the ground the bulb did not glow, even when a potential difference exists?
There is no potential difference across the bulb. Why should the bulb care if there is a potential difference somewhere else?
 
Elsa1234 said:
No this is not my circuit , the negative side of the bulb is connected to the ground instead of the negative terminal of the battery

This ... ?
cct1.GIF

If not that, where does the negative terminal of the battery go to then ?

You may now realize how unclear your original description wasDave
 
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davenn said:
so where does the negative terminal of the battery go to then ?

You may now realize how unclear your original description was
Everyone with a question about circuits should do us the courtesy of giving some sort of a labelled diagram.
 
indeed
 
  • #10
Electrons from the battery need to return to the battery, or within microseconds a charge imbalance will stop any more electrons from flowing. Electricity flows from the battery back into the battery, there is no loss or gain of electrons in the batter or in the lightbulb (ignoring that first microsecond). Wire is a good conductor, which means that it will allow current to flow with little resistance. In a good conductor like wire, current flow is ONE WAY. To be clear: the direction current can flow in a wire can change, but at anyone time current only flows in one direction. This means that if you connect a light bulb to one terminal of a battery, you aren't going to see anything happen. Only when you connect the other terminal of the battery to the other part of the lightbulb (so that current flows through the filament (assuming its incandescent)) and so that the electrons can go in on one wire and go out on the other at the same time will it light up.
 
  • #11
Elsa1234 said:
When I connected the positive terminal of the battery to one terminal of the bulb and the other terminal (of the bulb)to the ground the bulb did not glow, even when a potential difference exists?

There is no potential difference across the bulb. You appear to be assuming that the -ve terminal of the battery is at 0V with respect to ground. That's a mistake.

Lets say it's a 9v battery. The +ve terminal is connected to ground via the bulb. The -ve terminal of the battery is not connected to anything so it will be at roughly -9V (minus nine volts) with respect to ground. This is because the resistance of the bulb is much lower than the resistance of the open circuit on the -ve terminal.
 
  • #12
Perhaps consider a 9V battery still isolated in it's packaging. The -ve terminal is not necessarily at 0V with respect to ground. All you can really say is that the +ve terminal is +9V with respect to the -ve terminal. You can't be sure the +ve terminal is 9V with respect to ground until the -ve terminal is connected to ground.
 
  • #13
If this is proving difficult to the OP then why not reiterate the old, elementary rule which we learn in School 'You have to have a complete circuit'. Start with that and stick with it when trying to figure things out. The idea of Potential and Potential Difference involves a higher level of thinking.
 

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