Potential difference in multi cell circuit

[carlyn medona]

Homework Statement

Find potential difference between a and b in the figure

Homework Equations

Q=cv

The Attempt at a Solution

can anybody tell me how to apply the equation in this problem with more than one cell
[/B]

 

[Delta2]

Assuming that neither the batteries or the capacitors have ohmic resistance:

The capacitors are not exactly in series, however what can u say about the (transient) currents $I_1$ through the left capacitor and the current $I_2$ through the right capacitor? Are they equal? Why? And if they are equal what can you infer for the charges $Q_1$ and $Q_2$ of each capacitor?

 

[Abhishek kumar]

Homework Statement

Find potential difference between a and b in the figure

Homework Equations

Q=cv

The Attempt at a Solution

can anybody tell me how to apply the equation in this problem with more than one cell[/B]

Apply KVL which is potential difference in any close loop is zero

 

[carlyn medona]

So will potential difference between the two capacitors be equal and opposite, and I thought charge through them will be same, not sure, I am not good with multi cell circuits

 

[Delta2]

charges will be the same but voltages not necessarily. Apply KVL in the circuit knowing that the voltages at capacitors are $\frac{Q}{C_1}$ and $\frac{Q}{C_2}$.

 

[carlyn medona]

I applied loop rule and got v1+v2=0
Am I doing something wrong

 

[Abhishek kumar]

I applied loop rule and got v1+v2=0
Am I doing something wrong

I applied loop rule and got v1+v2=0
Am I doing something wrong[/QUOT
Yes you are not applying loop rule properly

 

[Delta2]

Are v1, v2 the voltages of capacitors or of the batteries?

 

[carlyn medona]

Capacitors

 

[Delta2]

Ok then you are correct. Now replace V1 , V2 with what I said at post 5 and find Q.

 

[carlyn medona]

But q is same and c is different and v1 +v2 =0 so is q equal to zero, so no charge pass through capacitor and have v1= v2=0