potential due to electric dipole is(adsbygoogle = window.adsbygoogle || []).push({});

V =p.r/ 4(pi)(epsilon)r^{3}

show the tangential component of the electrical field is

= psin(theta) / 4(pi)(epsilon)r^{3}

what ive tried:

i assumed there are 2 charges separated by distance r

potential difference U = qV = -qE.r

so can i say E[tangential] = V/r ?

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# Potential due to electric dipole

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