- #1

J-dizzal

- 394

- 6

## Homework Statement

The figure shows a plot of potential energy

*U*versus position

*x*of a 0.220 kg particle that can travel only along an

*x*axis under the influence of a conservative force. The graph has these values:

*UA*= 9 J,

*UC*= 20 J and

*UD*= 24 J. The particle is released at the point where

*U*forms a “potential hill” of “height”

*UB*= 12 J, with kinetic energy 7.00 J. What is the speed of the particle at

**(a)**

*x*= 3.5 m and

**(b)**

*x*= 6.5 m? What is the position of the turning point on

**(c)**the right side and

**(d)**the left side?

http://edugen.wileyplus.com/edugen/courses/crs7165/art/qb/qu/c08/q40.jpg

## Homework Equations

K=E-U

## The Attempt at a Solution

I know the turning point is when K=0 but not sure how to find that from this graph.