Potential energy curve, turning points

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SUMMARY

The discussion focuses on analyzing the potential energy curve of a 0.220 kg particle influenced by a conservative force. Key values include potential energies at points A (9 J), C (20 J), and D (24 J), with the particle starting at a potential hill height of 12 J and an initial kinetic energy of 7.00 J. The speed of the particle at positions x = 3.5 m and x = 6.5 m can be determined using the equation K = E - U, where K is kinetic energy and U is potential energy. The turning points occur where kinetic energy equals zero, which corresponds to the potential energy equaling the total mechanical energy of the system.

PREREQUISITES
  • Understanding of potential and kinetic energy concepts
  • Familiarity with conservative forces in physics
  • Knowledge of energy conservation principles
  • Ability to interpret potential energy graphs
NEXT STEPS
  • Calculate the speed of the particle at various positions using K = E - U
  • Identify the turning points by solving for when K = 0
  • Explore the implications of conservative forces on energy conservation
  • Review potential energy curves and their significance in mechanics
USEFUL FOR

Students studying classical mechanics, physics educators, and anyone interested in understanding the dynamics of particles under conservative forces.

J-dizzal
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Homework Statement


The figure shows a plot of potential energy U versus position x of a 0.220 kg particle that can travel only along an x axis under the influence of a conservative force. The graph has these values: UA = 9 J, UC = 20 J and UD = 24 J. The particle is released at the point where U forms a “potential hill” of “height” UB = 12 J, with kinetic energy 7.00 J. What is the speed of the particle at (a)x = 3.5 m and (b)x = 6.5 m? What is the position of the turning point on (c) the right side and (d) the left side?

http://edugen.wileyplus.com/edugen/courses/crs7165/art/qb/qu/c08/q40.jpg

Homework Equations


K=E-U

The Attempt at a Solution


I know the turning point is when K=0 but not sure how to find that from this graph.
 
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J-dizzal said:
I know the turning point is when K=0 but not sure how to find that from this graph.
Kinetic energy is zero when the potential energy is equal to the total energy.
 

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