Kinetic energy and work problem

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Homework Help Overview

The problem involves a block of ice sliding down a frictionless ramp at an angle while being pulled by a rope. The kinetic energy of the block increases as it moves down the ramp, and the question asks how much greater the kinetic energy would have been without the rope's influence.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the work done on the block and its relationship to kinetic energy changes. There are attempts to calculate total work and kinetic energy, with some questioning the correctness of their calculations.

Discussion Status

Participants are actively engaging with the problem, with some expressing uncertainty about their calculations and seeking clarification on the question's requirements. There is no clear consensus on the correct approach yet, but the discussion is focused on understanding the implications of the rope's force on kinetic energy.

Contextual Notes

Some participants note confusion regarding the interpretation of the question and the calculations involved, indicating a need for careful reading and consideration of the problem's parameters.

J-dizzal
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Homework Statement


In the figure here, a block of ice slides down a frictionless ramp at angle θ=55.0 ˚ while an ice worker pulls on the block (via a rope) with a force that has a magnitude of 54.0 N and is directed up the ramp. As the block slides down through distance d = 0.400 m along the ramp, its kinetic energy increases by 80.0 J. How much greater would its kinetic energy have been if the rope had not been attached to the block?

http://edugen.wileyplus.com/edugen/courses/crs7165/art/qb/qu/c07/fig_7_C.gif

Homework Equations


K=1/2 mv2, w=Fd, http://edugen.wileyplus.com/edugen/courses/crs7165/halliday9781118230725/c07/math/math080.gif, http://edugen.wileyplus.com/edugen/courses/crs7165/halliday9781118230725/c07/math/math082.gif

The Attempt at a Solution


The work done in the positive x dir is -21.6 because the box is sliding down, if the kinetic energy is 80J then 21.6J+80J=101.6J is the total. But this is not right.
http://i1164.photobucket.com/albums/q562/falsovero/20150630_163254_zps9et5lfe6.jpg [/B]
 
Last edited by a moderator:
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J-dizzal said:

Homework Statement


In the figure here, a block of ice slides down a frictionless ramp at angle θ=55.0 ˚ while an ice worker pulls on the block (via a rope) with a force that has a magnitude of 54.0 N and is directed up the ramp. As the block slides down through distance d = 0.400 m along the ramp, its kinetic energy increases by 80.0 J. How much greater would its kinetic energy have been if the rope had not been attached to the block?

http://edugen.wileyplus.com/edugen/courses/crs7165/art/qb/qu/c07/fig_7_C.gif

Homework Equations


K=1/2 mv2, w=Fd, http://edugen.wileyplus.com/edugen/courses/crs7165/halliday9781118230725/c07/math/math080.gif, http://edugen.wileyplus.com/edugen/courses/crs7165/halliday9781118230725/c07/math/math082.gif

The Attempt at a Solution


The work done in the positive x dir is -21.6 because the box is sliding down, if the kinetic energy is 80J then 21.6J+80J=101.6J is the total. But this is not right.
http://i1164.photobucket.com/albums/q562/falsovero/20150630_163254_zps9et5lfe6.jpg [/B]
What is the correct answer?

Read the question you're asked carefully.
"How much greater would its kinetic energy have been if the rope had not been attached to the block?"​
 
Last edited by a moderator:
its would be 101.6 - 80. would be the difference between the the work with the 54N and without?
 
Read the question you're asked carefully.
"How much greater would its kinetic energy have been if the rope had not been attached to the block?"​
thanks i need to work on this, it gets me often.
 

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