(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

Identical, massless springs, with spring constants k = 20 N/m, are connected in series, as shown. The springs are attached to rigid supports at x = ±L, where L = 59 cm. The equilibrium length of the springs is much smaller than the stretched length and can therefore be neglected in this problem.

There is also a diagram where the springs are on either side of a point and the positive x direction is to the right and the positive y direction is up

The connection point between the springs, initially at x=0 cm, y=0 cm, is pulled to x=17 cm, y=27 cm, and held there.

2. Relevant equations

What is the potential energy of the system now?

3. The attempt at a solution

It said hint:For this problem it is a good idea to use vectors in component form

so I said Usp(y)=.5(20)(.27^2) and then multiplied that by 2 for the y component

for the x component I said Usp(x)= -.5(20)(.59+.17)^2 + .5(20)(.59-.17)^2 for the x component.

I then tried to use the pythagorean theorum to find the missing side as the question needs only one answer ie. it can't be in vector form.

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# Homework Help: Potential energy of 2 sprinds on a single point

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