Potential Energy of a bottle w/ pressure

[fattydq]

I'm asked to calculate the potential energy of a 1 liter bottle with a pressure 10^4N/m^2 above atmospheric pressure.

I can't seem to find any formula in my book, or even through searching google extensively, that uses pressure and volume to calculate potential energy. Any ideas?

 

[rock.freak667]

The only thing I can think of is work done by gas = PV.

 

[fattydq]

I'm sorry could you clarify what you mean

 

[rock.freak667]

I'm sorry could you clarify what you mean

The only thing I can see happening with those values is the work done by the gas inside the bottle = pressure * volume.

 

[rwisz]

I can suggest using the formula for potential energy in a compressed gas system, which takes into account the pressure and volume of the gas. This formula is given by PE = (P1 - P2)V, where PE is the potential energy, P1 is the initial pressure, P2 is the final pressure, and V is the volume. In this case, P1 would be the pressure of the bottle at 10^4N/m^2 above atmospheric pressure, and P2 would be the atmospheric pressure. The volume of the bottle can be converted to cubic meters to ensure consistency in units. Using this formula, you can calculate the potential energy of the bottle. However, please note that this formula assumes an ideal gas and may not be accurate for all types of gases.