Potential energy per unit length in a string (sin wave)

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The discussion focuses on deriving the potential energy per unit length of a stretched string, specifically showing that it equals 1/2F(dy(x,t)/dx)^2. Participants clarify that the stretched length of the string is expressed as Δx(1+1/2(dy/dx)^2) and that the potential energy calculation involves understanding the difference between the stretched length and the original length. Confusion arises regarding the inclusion of the -Δx term in the numerator, leading to a deeper explanation of how the amount stretched differs from the total stretched length. The conversation emphasizes the importance of accurately representing these concepts in the equation to understand the potential energy derivation. Overall, the thread addresses key aspects of string mechanics and energy calculations.
PsychonautQQ
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Homework Statement



Given that the stretched length of a string is Δx(1+1/2(dy/dx)^2) show that the potential energy per unit length is equal to

1/2F(dy(x,t)/dx)^2


Homework Equations


potential energy = kx^2
cos(kx-wt)
idk really...


The Attempt at a Solution


The fact that the stretched length equals
Δx(1+1/2(dy/dx)^2)

can be derived from the fact that the strings stretched length is equal to (x^2+x(dy/dx)^2)^1/2
and then simplified with binomial expansion.

according to my answer key, the first step to the solution of solving potential energy per unit length is understanding that it is equal to
(FΔx(1+1/2(dy/dx)^2)-Δx) / Δx
The part about this step that I don't understand is why is the -Δx term in the numerator? Wouldn't the work per unit length just equal (Force * the amount it is stretched / Δx)? which would equal
FΔx(1+1/2(dy/dx)^2) / Δx.

yeah.. I don't understand why the -Δx is in the numerator i guess sums up my concerns.
 
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PsychonautQQ said:

The Attempt at a Solution


...the stretched length equals
Δx(1+1/2(dy/dx)^2)

according to my answer key, the first step to the solution of solving potential energy per unit length is understanding that it is equal to
(FΔx(1+1/2(dy/dx)^2)-Δx) / Δx

Should that be F(Δx(1+1/2(dy/dx)^2)-Δx) / Δx?

The part about this step that I don't understand is why is the -Δx term in the numerator? Wouldn't the work per unit length just equal (Force * the amount it is stretched / Δx)?

Yes, that's right. But "the amount it is stretched" is not the same as "the stretched length". For example, suppose I have a spring that has an unstretched length of 20 cm. (This is the length from one end of the spring to the other end when the spring is not stretched.) Then I stretch it until it has a "stretched length" of 30 cm. (This is the length from one end of the spring to the other when it is stretched.) The "amount it is stretched" would be 10 cm.
 
Yes, that's right. But "the amount it is stretched" is not the same as "the stretched length". For example, suppose I have a spring that has an unstretched length of 20 cm. (This is the length from one end of the spring to the other end when the spring is not stretched.) Then I stretch it until it has a "stretched length" of 30 cm. (This is the length from one end of the spring to the other when it is stretched.) The "amount it is stretched" would be 10 cm.

Cool, I'm still a little confused how that is represented in the equation by the term -Δx
 
Δx is the length of a section of string before it was stretched.

Δx(1+y'2/2) is the length of the same section after it has been stretched.

So, how would you write an expression for the amount the section has been stretched?
 
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