Find mass per unit length of a string graphically

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Homework Help Overview

The discussion revolves around determining the mass per unit length (μ) of a string graphically, using parameters such as frequency, tension, and mode of vibration. The original poster presents their calculations and attempts to confirm their results through graphical methods.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the original poster's calculations for μ and the graphical representation of the relationship between velocity and the square root of tension. Questions arise regarding the accuracy of the experimental value and the method of calculating wavelength.

Discussion Status

The discussion is ongoing, with participants questioning the calculations and exploring discrepancies between experimental and theoretical values. Some guidance is offered regarding the interpretation of the graph and the calculation of wavelength.

Contextual Notes

There are indications of potential errors in the original poster's calculations, as well as discussions about the setup of the experiment, including the string's configuration and measurement methods.

jbumbes
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Homework Statement


frequency, Tension, mass, mode of vibration

Homework Equations


v = sqrt(T/μ)

The Attempt at a Solution


length of string is 2.14m
weight .00247kg
mass per unit length (μ) .00089

However, I need to confirm this graphically. I solved for mass per unit length
μ = T/V^2
or sqrt(μ) = sqrt(T)/v
however, I have already graphed this and the slope is 33.5. With velocity on the y-axis and sqrt(T) on the x which seems way too off. Basically I have to find the experimental μ graphically.
 
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That gives an error of about 23% then - the difference between the experimental and real value for linear density?
You did take the wavelength to be the twice the distance between two adjacent nodes?
Is the string running straight from the top of the pulley to the other end where it is fixed or tied to the vibrator?
 
jbumbes said:
length of string is 2.14m
weight .00247kg
mass per unit length (μ) .00089
This in itself is strange. Can you explain how you calculated this ?
 
That is the experimentally determined value, which then gives a 23% difference between the two.
 
I mean that 2.47/2.14 is not 0.89 but 1.15 gram/meter
 
The 0.00089 value is from his gradient
 

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