Potential energy per unit length in a string (sin wave)

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Homework Help Overview

The discussion revolves around the potential energy per unit length in a stretched string, specifically in the context of wave mechanics. Participants are examining the relationship between the stretched length of the string and the potential energy derived from it.

Discussion Character

  • Conceptual clarification, Mathematical reasoning, Assumption checking

Approaches and Questions Raised

  • Participants are attempting to understand the derivation of the stretched length formula and its implications for calculating potential energy. Questions are raised about the inclusion of the -Δx term in the potential energy expression and the distinction between "stretched length" and "amount stretched."

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of the terms involved in the equations. Some guidance has been provided regarding the definitions of stretched length and the amount stretched, but confusion remains about their representation in the equations.

Contextual Notes

There is a focus on the mathematical relationships involved in the problem, with participants questioning the assumptions underlying the expressions used. The original poster references an answer key, indicating a structured approach to the problem, but there is uncertainty about specific terms in the equations.

PsychonautQQ
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Homework Statement



Given that the stretched length of a string is Δx(1+1/2(dy/dx)^2) show that the potential energy per unit length is equal to

1/2F(dy(x,t)/dx)^2


Homework Equations


potential energy = kx^2
cos(kx-wt)
idk really...


The Attempt at a Solution


The fact that the stretched length equals
Δx(1+1/2(dy/dx)^2)

can be derived from the fact that the strings stretched length is equal to (x^2+x(dy/dx)^2)^1/2
and then simplified with binomial expansion.

according to my answer key, the first step to the solution of solving potential energy per unit length is understanding that it is equal to
(FΔx(1+1/2(dy/dx)^2)-Δx) / Δx
The part about this step that I don't understand is why is the -Δx term in the numerator? Wouldn't the work per unit length just equal (Force * the amount it is stretched / Δx)? which would equal
FΔx(1+1/2(dy/dx)^2) / Δx.

yeah.. I don't understand why the -Δx is in the numerator i guess sums up my concerns.
 
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PsychonautQQ said:

The Attempt at a Solution


...the stretched length equals
Δx(1+1/2(dy/dx)^2)

according to my answer key, the first step to the solution of solving potential energy per unit length is understanding that it is equal to
(FΔx(1+1/2(dy/dx)^2)-Δx) / Δx

Should that be F(Δx(1+1/2(dy/dx)^2)-Δx) / Δx?

The part about this step that I don't understand is why is the -Δx term in the numerator? Wouldn't the work per unit length just equal (Force * the amount it is stretched / Δx)?

Yes, that's right. But "the amount it is stretched" is not the same as "the stretched length". For example, suppose I have a spring that has an unstretched length of 20 cm. (This is the length from one end of the spring to the other end when the spring is not stretched.) Then I stretch it until it has a "stretched length" of 30 cm. (This is the length from one end of the spring to the other when it is stretched.) The "amount it is stretched" would be 10 cm.
 
Yes, that's right. But "the amount it is stretched" is not the same as "the stretched length". For example, suppose I have a spring that has an unstretched length of 20 cm. (This is the length from one end of the spring to the other end when the spring is not stretched.) Then I stretch it until it has a "stretched length" of 30 cm. (This is the length from one end of the spring to the other when it is stretched.) The "amount it is stretched" would be 10 cm.

Cool, I'm still a little confused how that is represented in the equation by the term -Δx
 
Δx is the length of a section of string before it was stretched.

Δx(1+y'2/2) is the length of the same section after it has been stretched.

So, how would you write an expression for the amount the section has been stretched?
 
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