Potential of Shell, Direct integration problems

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Homework Help Overview

The discussion revolves around calculating the electric potential of a uniformly charged conducting spherical shell using direct integration. The problem specifically asks for the potential at points both inside and outside the shell, with participants exploring the implications of applying Gauss's law versus direct integration methods.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the need to divide the spherical shell into slices for integration and question how to correctly set up the integral for the potential. There is mention of difficulties in applying Gauss's law and integrating over the surface charge density.

Discussion Status

The discussion is ongoing, with participants sharing their attempts and expressing confusion about the integration process. Some have provided suggestions for approaching the problem, but there is no clear consensus on the correct method yet.

Contextual Notes

Participants are grappling with the requirement of direct integration as opposed to using Gauss's law, and there are uncertainties regarding the setup of the integral and the calculation of differential charge elements.

physapple89
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Homework Statement



Okay I'm really scratching my brain out here, I've done this a thousand times but aparantly NOT the correct way, here's the problem

A conducting spherical shell of radius R is charged uniformly with total charge Q. By DIRECT integration, find the potential at an arbitrary point r with A)r<R and B)r>R

Homework Equations



V=Q/(4*pi*epsilon*r)

someone also showed me

2}}.gif




The Attempt at a Solution



I started out by noting that inside the sphere for any gaussian surface you can draw the total charge density will be 0 and therefore the E field will be 0, and because of that the Voltage will be constant which turns the integral for voltage into two parts

gif.latex?V=\int_{\infty%20}^{R}E*dl-\int_{R}^{0}0*dl.gif


Integration then yields typical results, which while correct, are utterly wrong for the purposes of this question, as it is asking for DIRECT integration, Can anyone help, this isn't making any sense?
 
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welcome to pf!

hi physapple89! welcome to pf! :wink:

divide the spherical shell into slices perpendicular to the line joining the point to the centre of the shell …

(so all points on the same slice will be at the same distance)

integrate over all the slices …

what do you get? :smile:
 
I think that's the part I'm not getting how to do.
 
ok, show us what you've tried, and where you're stuck, and then we'll know how to help! :smile:
 
What I tried was up there, using gauss's law but it didn't quite work, then I tried integrating over the area of the shpere times the surface charge density and that didn't work. I don't think I'm setting this up right.

Basically I need help solving for the dQ so that I can integrate.
 
is this the correct integral?

2}}.gif


basically integrating over the sphere times surface charge density and plugging that into the previous equation.
 

Attachments

  • CodeCogsEqn(2).gif
    CodeCogsEqn(2).gif
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http://www.kwantlen.bc.ca/science/physics/faculty/mcoombes/P2420_Solutions/VfromCharge/P2420_09_Solutions.htm

does this explain what I'm trying to find, can anyone tell mehow they got dA?
 
Last edited by a moderator:
i don't understand how you calculated √(r2R2 - 2rRcosθ) :confused:

"A" comes from 2π times the radius of a "circle of latitude"

start again :smile:
 

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