Potential ##V## and potential energy ##E_{pot}##?

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SUMMARY

The discussion clarifies the relationship between potential energy (##E_{pot}##) and potential (##V##) in the context of springs and electric fields. It establishes that for springs, the potential energy is given by the formula ##E_{pot} = \frac{1}{2}kx^2##, while the potential is also expressed as ##V = \frac{1}{2}kx^2##. The key distinction lies in the fact that potential energy is an absolute measure, while potential is a relative measure per unit charge in electric fields. The terms are often used interchangeably in contexts where the distinction is less critical, particularly in gravitational fields.

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  • Understanding of potential energy and potential in physics
  • Familiarity with Hooke's Law and spring mechanics
  • Basic knowledge of electric fields and their properties
  • Mathematical proficiency in manipulating equations involving energy and force
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  • Study the differences between gravitational potential energy and electric potential energy
  • Explore Hooke's Law in-depth and its applications in mechanical systems
  • Learn about electric fields and the concept of electric potential
  • Investigate the implications of potential energy in various physical systems
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Students of physics, educators teaching mechanics and electromagnetism, and anyone interested in understanding the nuances of potential and potential energy in different contexts.

Abigale
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Hi,
I know that in an elecric field the potential energy ##E_{pot}## is equal to the potential ##V## times the charge ##E_{pot}=q V##.

Here my problem:
I know that the potential energy of a spring is ##E_{pot}= \frac{1}{2}kx^2##.
In my theoretical physics book i read also that the potential is ##V=\frac{1}{2}kx^2## for a spring.

Is the potential and potential energy for a spring exactly the same?
And why?
 
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Abigale said:
Hi,
I know that in an elecric field the potential energy ##E_{pot}## is equal to the potential ##V## times the charge ##E_{pot}=q V##.

Here my problem:
I know that the potential energy of a spring is ##E_{pot}= \frac{1}{2}kx^2##.
In my theoretical physics book i read also that the potential is ##V=\frac{1}{2}kx^2## for a spring.

Is the potential and potential energy for a spring exactly the same?
And why?

The main difference between these two scenarios is that the spring has an inherent potential energy, but the electric field has an inherenet potential energy per unit charge: which gives the potential energy of a particle depending on its charge.
 
Abigale said:
I know that the potential energy of a spring is ##E_{pot}= \frac{1}{2}kx^2##.
In my theoretical physics book i read also that the potential is ##V=\frac{1}{2}kx^2## for a spring.

Is the potential and potential energy for a spring exactly the same?
And why?

In this case, yes, it is the same thing.

The terms "potential" and "potential energy" are often intermixed, especially when the non-energy form of "potential" is not relevant or not used often enough, as in the case of gravitational field. This is different from the electric field case where we do use electric potential and electric potential energy more frequently. So often times, in gravity case, book authors often tend to go sloppy.

You will encounter many times where the terminology may change and vary from book to book, person to person, situation to situation. It is why it is extremely important not to get too attached to a particular symbol or label being given to something. It is more important that you look at the mathematical form or definition of that thing, because THAT is the only description that matters, not the name we give to it.

Zz.
 
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